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TauCeti.NumberTheory.NumberField.Global.Orders.Quadratic.Basic

Proper ideals of quadratic orders are invertible #

In an order O of a quadratic number field K, a fractional ideal is proper (its multiplier ring is exactly O) if and only if it is invertible. In higher degree only the implication from invertible to proper survives; the cubic order ℤ + 2ℤ∛2 + 2ℤ∛4 has a proper noninvertible ideal. So for quadratic orders the Picard group Pic O sees every proper ideal class, which is what lets the ring class group of a quadratic order be described by proper ideals or, equivalently, by primitive binary quadratic forms.

The proof is Cox's. Write a nonzero fractional ideal as a lattice I = ℤα + ℤβ and put τ = β / α, a root of a primitive integral quadratic a τ² - b τ - e = 0 (gcd (a, b, e) = 1). Then a τ preserves I, so it lies in O when I is proper. With τ' = b / a - τ the conjugate of τ, the elements a / α and a τ' / α carry I into O, and the products of α, β ∈ I with them are a, b and -e up to integer combinations. Since a, b and e generate the unit ideal of ℤ, the product of I with 1 / I = (O : I) contains 1, so it is the unit ideal.

Main results #

In the namespace TauCeti.GlobalNumberFields.NumberFieldOrder:

References #

A proper fractional ideal of a quadratic order is invertible (Cox, Lemma 7.5).

Proper and invertible fractional ideals coincide in a quadratic order. In higher degree only invertible ideals are guaranteed to be proper.