The prime-splitting law for a quadratic field #
For a quadratic number field K = ℚ(√d) — given as K generated over ℚ by an algebraic
integer θ whose minimal polynomial over ℤ is X² - d — and an odd prime p not dividing
d, the prime p splits completely in K (there are [K:ℚ] = 2 primes of 𝓞 K above it) if
and only if d is a quadratic residue mod p, i.e. legendreSym p d = 1.
The proof routes through Mathlib's number-field Kummer–Dedekind theorem
(primesOverSpanEquivMonicFactorsMod): the primes above p biject with the monic irreducible
factors of X² - d mod p, of which there are two exactly when d is a square mod p. The
required conductor hypothesis p ∤ exponent θ follows because the conductor exponent divides the
power-basis discriminant 4d, which is coprime to the odd prime p ∤ d.
This is the base case n = 1 of the multiquadratic prime-splitting law.
The splitting law is then read off at the level of ideals: a completely split rational prime is
the absolute norm of a prime of 𝓞 K
(Ideal.absNorm_eq_of_ncard_primesOver_eq_finrank). That is the shape in which the
splitting law enters genus theory, where an ideal of norm p is what carries the prescribed
values of the genus characters.
The prime 2 is handled separately, through the count of primes above 2 for a generator with
minimal polynomial X² - X + c and odd conductor exponent
(NumberField.ncard_primesOver_two_of_minpoly_eq_X_sq_sub_X_add, in
TauCeti.NumberTheory.NumberField.Ideal.KummerDedekind). Such a generator always has odd
conductor exponent, since X² - X + c is separable modulo 2
(not_two_dvd_exponent_of_minpoly_eq_X_sq_sub_X_add, in the same file). For c = (1 - d)/4 with
d ≡ 1 (mod 4),
the presentation of ℚ(√d) by (1 + √d)/2, 2 splits exactly when d ≡ 1 (mod 8) and is inert
exactly when d ≡ 5 (mod 8). For K = ℚ(√d) presented by θ with θ² = d and d ≡ 1 (mod 4),
the half-integer generator (1 + θ)/2 (halfGen) has minimal polynomial X² - X + (1 - d)/4
(minpoly_halfGen) and generates K over ℚ (adjoin_rat_halfGen_eq_top), and (1 - d)/4 is
even exactly when d ≡ 1 (mod 8); the generator θ itself is useless here, since 2 divides
its conductor exponent. No squarefreeness of d is needed.
Main results #
NumberField.ncard_primesOver_quadratic_iff: the quadratic splitting law at an odd prime.NumberField.exists_isPrime_and_absNorm_eq_of_legendreSym_eq_one: an odd primepwithlegendreSym p d = 1is the absolute norm of a prime ideal of𝓞 K.NumberField.ncard_primesOver_two_eq_finrank_iff_of_minpoly_eq_X_sq_sub_X_addandNumberField.ncard_primesOver_two_eq_one_iff_of_minpoly_eq_X_sq_sub_X_add: for a generator with minimal polynomialX² - X + (1 - d)/4andd ≡ 1 (mod 4),2splits iffd ≡ 1 (mod 8)and is inert iffd ≡ 5 (mod 8).NumberField.ncard_primesOver_two_of_mod_four_eq_one: the number of primes above2isif d % 8 = 1 then 2 else 1forℚ(√d)withd ≡ 1 (mod 4), presented by√d, with the corollariesNumberField.ncard_primesOver_two_eq_finrank_iff_of_mod_four_eq_one(2splits iffd ≡ 1 (mod 8)) andNumberField.ncard_primesOver_two_eq_one_iff_of_mod_four_eq_one(2is inert iffd ≡ 5 (mod 8)).
References #
- J. Neukirch, Algebraic Number Theory, Chapter I, §8, Proposition (8.3).
The quadratic splitting law. For K = ℚ(√d) (θ a square root of the integer d
generating K) and an odd prime p ∤ d, p splits completely in K iff d is a quadratic
residue mod p. This is the n = 1 case of the multiquadratic prime-splitting law.
A split prime is an ideal norm. For K = ℚ(√d) and an odd prime p for which d is a
quadratic residue mod p — that is, one which splits in K by
ncard_primesOver_quadratic_iff — there is a prime ideal of 𝓞 K of absolute norm p. This is the
form in which the splitting law feeds genus theory: the genus characters are computed on ideals
through their absolute norms.
The prime 2 for d ≡ 1 (mod 4) #
The splitting law at 2 for a generator with minimal polynomial X² - X + (1 - d)/4. Let
K be generated over ℚ by an algebraic integer ω with minimal polynomial X² - X + (1 - d)/4
over ℤ, where d ≡ 1 (mod 4) — the presentation of ℚ(√d) by ω = (1 + √d)/2. Then 2
splits completely in K if and only if d ≡ 1 (mod 8).
The inert case at 2 for a generator with minimal polynomial X² - X + (1 - d)/4. Let
K be generated over ℚ by an algebraic integer ω with minimal polynomial X² - X + (1 - d)/4
over ℤ, where d ≡ 1 (mod 4). Then 2 is inert in K (there is a single prime above it) if
and only if d ≡ 5 (mod 8).
The number of primes above 2 for d ≡ 1 (mod 4). For K = ℚ(√d) with d ≡ 1 (mod 4),
there are two primes of 𝓞 K above 2 when d ≡ 1 (mod 8) and one when d ≡ 5 (mod 8): the
half-integer generator (1 + √d)/2 has minimal polynomial X² - X + (1 - d)/4 and odd conductor
exponent, and (1 - d)/4 is even exactly when d ≡ 1 (mod 8).
The splitting law at 2 for d ≡ 1 (mod 4). For K = ℚ(√d) with d ≡ 1 (mod 4), the
prime 2 splits completely in K if and only if d ≡ 1 (mod 8).
The inert case at 2 for d ≡ 1 (mod 4). For K = ℚ(√d) with d ≡ 1 (mod 4), the
prime 2 is inert in K (there is a single prime above it) if and only if d ≡ 5 (mod 8).