The dyadic ramification of ℚ(i) #
For K generated over ℚ by an algebraic integer θ with minpoly ℤ θ = X² + 1, the prime
2 divides the discriminant −4, so it ramifies: the prime 𝔭 = (1 + θ) is the only prime of
𝓞 K above 2, with e = 2, f = 1 and 2 𝓞 K = 𝔭². The different of the monogenic ring
𝓞 K = ℤ[θ] is generated by f'(θ) = 2θ, and θ is a unit, so 𝔡 = (2) = 𝔭²: the different
exponent v_𝔭(𝔡) = 2 equals the ramification index. This is the wild dyadic case, where the
lower bound e of the different exponent is attained and the tame formula e − 1 fails. Since
v_𝔭(e) = v_𝔭(2) = 2, the upper bound e − 1 + v_𝔭(e) = 3 of Dedekind's different theorem is
strict here; it is attained in ℚ(√2)
(TauCeti.NumberField.Sqrt2.multiplicity_differentIdeal_eq_ramificationIdx_sub_one_add).
Main results #
TauCeti.NumberField.GaussianRationals.two_mem_ramifiedPrimes:2ramifies, andncard_primesOver_two_eq_one: there is one prime above it.TauCeti.NumberField.GaussianRationals.eq_span_one_add: the prime above2is(1 + θ).TauCeti.NumberField.GaussianRationals.ramificationIdx_eq_two,ramificationIdxIn_two_eq_two,inertiaDeg_eq_one,map_span_two_eq_sq:e = 2,f = 1, and2 𝓞 K = 𝔭².TauCeti.NumberField.GaussianRationals.differentIdeal_eq_span_two:𝔡 = (2).TauCeti.NumberField.GaussianRationals.differentIdeal_eq_sqandmultiplicity_differentIdeal_eq_two:𝔡 = 𝔭², that isv_𝔭(𝔡) = 2.TauCeti.NumberField.GaussianRationals.multiplicity_span_two_eq_two:v_𝔭(2) = 2, andmultiplicity_differentIdeal_lt_ramificationIdx_sub_one_add:v_𝔭(𝔡) < e − 1 + v_𝔭(e).
2 ramifies in ℚ(i): it divides the discriminant −4.
The ideal (1 + θ) has absolute norm 2: N(1 + θ) = 1² − (−1) · 1².
There is a single prime of 𝓞 K above 2.
The ramification index of 2 in ℚ(i) is 2, in the form that does not name a prime
above 2.
The different of ℚ(i) is (2): the different of ℤ[θ] is generated by
f'(θ) = 2θ, and θ is a unit.
The prime above 2 in ℚ(i) is (1 + θ).
2 is totally ramified in ℚ(i): e(𝔭 ∣ 2) = 2.
The prime above 2 in ℚ(i) has residue degree 1.
2 𝓞 K = 𝔭² in ℚ(i).
The different of ℚ(i) is 𝔭²: 𝔡 = (2) = 𝔭².
The different exponent at the dyadic prime is 2 = e: v_𝔭(𝔡) = 2, the wild lower
bound attained.
The dyadic valuation of 2 in ℚ(i) is 2: v_𝔭(2) = 2.
The wild upper bound is strict in ℚ(i): at the dyadic prime,
v_𝔭(𝔡) = 2 < 3 = e − 1 + v_𝔭(e).