The Lindemann–Weierstrass theorem over a Galois number field #
Let K be a number field, Galois over ℚ, together with an embedding of K into ℂ (an
Algebra K ℂ structure). A formal exponential sum x = ∑ δ_γ [γ] ∈ K[K] evaluates to the complex
number expEval K x = ∑ δ_γ exp γ. This file proves that this evaluation is injective: distinct
elements of K have K-linearly independent exponentials.
expEval_ne_zero_of_forall_galConj_eq: the weak Lindemann–Weierstrass theorem. A nonzero formal sum fixed by the conjugationsgalConj τ,τ ∈ Gal(K/ℚ), does not evaluate to0.expEval_injective: the evaluationexpEval K : K[K] →ₐ[K] ℂis injective. The product of the conjugates of a formal sumxis Galois-invariant, it is nonzero whenxis sinceK[K]is a domain, and its evaluation vanishes when that ofxdoes.linearIndependent_exp_algebraMap: the same statement as linear independence of the familyγ ↦ exp γof exponentials of the elements ofK.
The weak theorem follows Hermite's argument. After clearing denominators, the coefficients δ_γ
are algebraic integers and l γ is an algebraic integer for a positive integer l and every
γ in the support S of x. Fix γ₀ ∈ S. For large primes p the auxiliary value
a = auxValue x l p γ₀ is a nonzero algebraic integer (auxValue_ne_zero,
isIntegral_auxValue), so some complex conjugate of a has absolute value at least 1
(NumberField.exists_conjugate_one_le_norm). Since K / ℚ is normal and x is
Galois-invariant, the conjugates of a are the auxiliary values at the conjugates of γ₀
(auxValue_galConj), and if expEval K x = 0 these all have absolute value less than 1 for
large p (eventually_norm_auxValue_lt_one).
References #
- J.-H. Evertse, Diophantine Approximation (2019), ch. 4, §4.2, Theorem 4.11 and its proof, and the deduction of Theorem 4.8 from it.
- Y. Zhao, formalization of the Lindemann–Weierstrass theorem in Lean,
Basic.lean, which reduces to Galois-invariant exponential sums by taking the product of all conjugates.
The weak Lindemann–Weierstrass theorem. Let K be a number field, Galois over ℚ and
embedded in ℂ. If a nonzero formal exponential sum x = ∑ δ_γ [γ] ∈ K[K] is fixed by the
conjugation galConj τ for every τ ∈ Gal(K/ℚ), then ∑ δ_γ exp γ ≠ 0.
The Lindemann–Weierstrass theorem over a Galois number field. Let K be a number field,
Galois over ℚ and embedded in ℂ. Then the exponential evaluation
∑ δ_γ [γ] ↦ ∑ δ_γ exp γ of formal sums in K[K] is injective: the exponentials of distinct
elements of K are linearly independent over K.
The Lindemann–Weierstrass theorem over a Galois number field, linear independence form.
Let K be a number field, Galois over ℚ and embedded in ℂ. Then the exponentials of the
elements of K are linearly independent over K.