Product-one triples generating a subgroup #
The Frobenius formula counts all product-one triples in three conjugacy classes of a finite group. To count covers with prescribed monodromy, one must also require that the first two entries generate the specified subgroup. Every product-one triple belongs to exactly one generation stratum, indexed by the subgroup generated by its first two entries. This file states the resulting subgroup-lattice recursion for the counts.
The classes remain classes of the ambient group throughout: intersecting them with a subgroup does not in general produce a single conjugacy class of that subgroup.
The subgroup generated by the first two entries of a triple. For a product-one triple, the third entry belongs to this subgroup as well.
Equations
- TauCeti.productOneGeneratedSubgroup p = Subgroup.closure {p.1, p.2.1}
Instances For
The subgroup generated by a triple is the closure of its first two entries.
A homomorphism sends the subgroup generated by the first two entries to the subgroup generated by their images.
The product-one triples in three ambient conjugacy classes whose entries lie in H.
It suffices to check the first two entries, since the product-one equation determines the
third.
Equations
- TauCeti.productOneTriplesIn C0 C1 Cinf H = {p ∈ TauCeti.productOneTriples C0 C1 Cinf | p.1 ∈ H ∧ p.2.1 ∈ H}
Instances For
The third entry also lies in H: the product-one equation forces it to be the inverse
of the product of the first two entries.
The triples in three ambient classes that generate exactly H.
Equations
- TauCeti.generatingProductOneTriples C0 C1 Cinf H = {p ∈ TauCeti.productOneTriples C0 C1 Cinf | TauCeti.productOneGeneratedSubgroup p = H}
Instances For
A generating product-one triple lies in the subgroup it generates.
Restricting product-one triples to the whole group changes nothing.
Subgroup-lattice partition. Every product-one triple in H generates a unique
subgroup K ≤ H. The conjugacy classes are those of G, even when K is proper.
The Frobenius count splits into generating counts over all subgroups.
Downward recursion. The count generating H is the total count of product-one
triples in H minus the counts generating its proper subgroups.
The downward recursion determines the generating counts uniquely. Thus one can compute them from the total counts in subgroups without enumerating the generating triples themselves.