The commutant of the orthogonal group on the tensor square #
Let K be a field and V = Kⁿ with its standard symmetric bilinear form. The Brauer algebra
B₂(n) on two strands has three diagrams: the identity, the crossing σ and the cap-cup e. Its
action TauCeti.brauerActionOrth on V ⊗ V sends them to the identity, the flip of the two tensor
factors, and the map x ⊗ y ↦ ⟨x, y⟩ ∑ⱼ eⱼ ⊗ eⱼ. These operators commute with the diagonal action
g ↦ g ⊗ g of the orthogonal group O(n, K) (TauCeti.range_brauerActionOrth_le_centralizer).
This file proves the converse on two strands when 2 ≠ 0 in K and the unit circle of K has a
point (c, s) with c s ≠ 0, in particular in characteristic zero: every operator on V ⊗ V
commuting with every g ⊗ g is a combination of the identity, σ and e, so the image of B₂(n)
is exactly the commutant of O(n, K)
(TauCeti.range_brauerActionOrth_two_eq_centralizer_of_sq_add_sq_eq_one, and
TauCeti.range_brauerActionOrth_two_eq_centralizer in characteristic zero). This is the
two-strand case of Brauer's description of the commutant of the orthogonal group on
V^{⊗k}, the first fundamental theorem of invariant theory for O(n).
The proof is a computation with the matrix M of such an operator in the monomial basis
eₐ ⊗ e_b, using three kinds of orthogonal matrices.
- The diagonal reflections
diag(±1, …, ±1)forceMto vanish at every entry whose four indices do not pair off. An entryM_{(a,b),(c,d)}can only be nonzero whena = bandc = d, when(a, b) = (c, d), or when(a, b) = (d, c). - The permutation matrices make
Minvariant under renaming the indices, so on each of these three patterns with two distinct indicesMis constant. SoM = q • 1 + r • σ + p • e + y • Δ, whereΔis the diagonal projection onto the span of theeₐ ⊗ eₐ. - A reflection
gwithg₀₀ g₀₁ ≠ 0does not commute withΔ, soy = 0.
The last step needs such a reflection. Its entries come from a point (c, s) of the unit circle
with c s ≠ 0, which exists over every field of characteristic zero, for instance (3/5, 4/5);
the diagonal reflections need 2 ≠ 0. The unit-circle condition cannot be dropped: over 𝔽₃
with n = 2 the orthogonal group consists of the signed permutation matrices, and Δ commutes
with all of them without lying in the image of B₂(2).
Main results #
TauCeti.eq_and_eq_or_eq_or_eq_and_eq_of_forall_update_mul_eq: when2 ≠ 0, if every sign vectorFunction.update 1 a (-1)gives the same product of signs on two pairs of indices, the four indices pair off.TauCeti.range_brauerActionOrth_two_eq_centralizer_of_sq_add_sq_eq_one: over a field with2 ≠ 0and a point(c, s)of the unit circle withc ≠ 0ands ≠ 0, the image of the Brauer algebraB₂(n)is the commutant of the orthogonal group on(Kⁿ)^{⊗2}.TauCeti.range_brauerActionOrth_two_eq_centralizer: the same over every field of characteristic zero.
References #
- R. Brauer, On algebras which are connected with the semisimple continuous groups, Annals of Mathematics 38 (1937), 857-872.
- R. Goodman and N. R. Wallach, Symmetry, Representations, and Invariants, Springer GTM 255 (2009), Chapter 5 (the first fundamental theorem for the orthogonal group) and §10.1.
Let 2 ≠ 0 in R. If, for every a, the sign vector Function.update 1 a (-1) (the diagonal
of TauCeti.orthogonalDiagonalReflection R a) gives the same product of signs on the two pairs of
indices (v 0, v 1) and (u 0, u 1), then the four indices pair off: the two pairs are both
constant, or equal, or swapped.
Brauer duality on the tensor square. Over a field K with 2 ≠ 0 that has a point
(c, s) of the unit circle with c ≠ 0 and s ≠ 0, the image of the Brauer algebra B₂(n) in
the endomorphisms of (Kⁿ)^{⊗2} is the commutant of the diagonal action of the orthogonal group:
an operator commuting with every g ⊗ g is a combination of the identity, the flip of the two
tensor factors and the cup-cap generator.
Brauer duality on the tensor square in characteristic zero. Over a field of
characteristic zero, the image of the Brauer algebra B₂(n) in the endomorphisms of (Kⁿ)^{⊗2}
is the commutant of the diagonal action of the orthogonal group.