The invariant tensors of an irreducible unitary representation are at most a line #
For an irreducible unitary representation π of a monoid on a finite-dimensional inner product
space over an algebraically closed field, the invariants of the tensor square are at most
one-dimensional, and consequently so are the invariants of the symmetric and of the exterior
square together:
dim (Sym²V)ᴳ + dim (Λ²V)ᴳ ≤ 1.
That inequality is the whole content of the Frobenius-Schur trichotomy: the indicator is the
difference of those two dimensions
(ContRepresentation.frobeniusSchurIndicator_eq_sub_finrank_invariants), so an inequality on their
sum pins the difference to 1, 0 or -1.
The argument is Schur's lemma applied through a contraction. An orthonormal basis e carries the
bilinear form B(v, w) = ⟪J v, w⟫ and the contraction
TauCeti.tensorSquareEquivEnd e : V ⊗[𝕜] V ≃ₗ[𝕜] (V →ₗ[𝕜] V); unitarity of π makes B invariant
for the pair (π, {}^J π), where {}^J π = OrthonormalBasis.conjugate e π is the
conjugate representation, so an invariant tensor contracts to an intertwiner {}^J π ⟶ π.
Schur's lemma makes a nonzero such intertwiner surjective, hence bijective, and then every other
one is a scalar multiple of it, because the two composed through the inverse commute with π.
Pulling that back along the contraction, which is injective, says the invariant tensors are a line.
Only the target π of those intertwiners has to be irreducible, which is why the conjugate
representation is never itself shown irreducible: surjectivity of a nonzero intertwiner needs
irreducibility of the target only, and injectivity then comes from finite-dimensionality.
The symmetric and the antisymmetric tensors are invariant submodules that meet in 0
(TauCeti.isCompl_symmetricTensors_antisymmetricTensors), so their invariants sit inside the
invariants of the tensor square as two submodules in direct sum, and the bound on the sum follows
from the bound on the tensor square.
Main statements #
ContRepresentation.finrank_invariants_tprod_self_le_one: the invariant tensors of an irreducible unitary representation are at most a line.ContRepresentation.finrank_invariants_squares_le_one: the two invariant counts that the Frobenius-Schur indicator subtracts add up to at most1.ContRepresentation.tensorSquareEquivEnd_conjCLM_of_mem_invariants: the contraction of an invariant tensor intertwines the conjugate representation withπ.
Implementation notes #
All declarations sit in the root ContRepresentation namespace, so that dot notation on
Mathlib's ContRepresentation elaborates and scripts/lint-dot-notation.py is satisfied; the
ambient TauCeti names are brought in by open, following
TauCeti/RepresentationTheory/Continuous/Square/Basic.lean.
The statements that do not name a contraction take no orthonormal basis: a finite-dimensional
inner product space has stdOrthonormalBasis, and the bounds do not depend on which basis is
used. The conjugate representation appears only through TauCeti.conjCLM, never through a
statement about its irreducibility or its character.
References #
The Frobenius-Schur reality trichotomy itself is in
TauCeti/RepresentationTheory/Compact/FrobeniusSchur/Trichotomy.lean. The mathematical development
follows Daniel Bump, Lie Groups, second edition, Chapter 2, and T. Bröcker and T. tom Dieck,
Representations of Compact Lie Groups, Springer GTM 98 (1985), Chapter II.
The bilinear form of an orthonormal basis is invariant for π against its conjugate. The
two conjugations cancel against the unitarity of π, which is the identity that makes the
contraction of an invariant tensor an intertwiner.
Contracting the tensor square commutes with the action, up to conjugating the argument: the
contraction of (π g ⊗ π g) t at {}^J(π g) u is π g of the contraction of t at u.
The contraction of an invariant tensor intertwines the conjugate representation with π.
The intertwiner {}^J π ⟶ π that an invariant tensor contracts to.
Equations
- One or more equations did not get rendered due to their size.
Instances For
A nonzero invariant tensor contracts to a bijection: its contraction is a nonzero
intertwiner into the irreducible π, hence surjective, and in finite dimensions surjective is
bijective.
Any two invariant tensors of an irreducible unitary representation are proportional, once
one of them is nonzero: composing the contraction of the second with the inverse of the contraction
of the first gives a self-intertwiner of π, which Schur's lemma makes a scalar.
The invariant tensors of an irreducible unitary representation are at most a line. They are all proportional to any nonzero one of them.
The two invariant counts the Frobenius-Schur indicator subtracts add up to at most 1. The
symmetric and the antisymmetric tensors meet in 0, so their invariants sit in direct sum inside
the invariants of the tensor square, which are at most a line.