Bounding H² of a finite solvable group from its cyclic subquotients #
Let A be a representation of a finite solvable group G. Suppose that H¹(H, A) = 0 for every
subgroup H of G, and that for every normal subgroup N of prime index in such an H the
order of H²(H ⧸ N, A^N) divides [H : N]. Then the order of H²(G, A) divides #G
(natCard_groupCohomology_two_dvd_natCard); in particular H²(G, A) is finite.
This is how the upper bound #H²(Gal(L/K), Lˣ) ≤ [L : K] for a finite Galois extension of local
fields is reduced to cyclic extensions of prime degree: Gal(L/K) is solvable, Hilbert's
Theorem 90 gives the vanishing of H¹, and the cyclic case is a Herbrand quotient computation.
Main statements #
TauCeti.groupCohomology.natCard_groupCohomology_two_dvd_natCard: the order ofH²(G, A)divides#G.
References #
- J.-P. Serre, Local class field theory, in J. W. S. Cassels and A. Fröhlich (eds.), Algebraic Number Theory, Chapter VI, §1.
- J. S. Milne, Class Field Theory, v4.03, Chapter III, §2.
H² of a finite solvable group is bounded by its cyclic subquotients. Let A be a
representation of a finite solvable group G. Suppose that H¹(H, A) = 0 for every subgroup H
of G (given as an injective homomorphism f : H →* G), and that for every normal subgroup N
of prime index in such an H, the order of H²(H ⧸ N, A^N) divides [H : N]. Then the order of
H²(G, A) divides #G; in particular H²(G, A) is finite.