Relabeling a Young tableau conjugates its Young symmetrizer #
A Young symmetrizer, and with it the left ideal ℚ[Sₙ] c_t it generates, is built from a
μ-tableau t, while the Specht module it presents is meant to depend only on the shape μ.
This file supplies that independence.
Relabeling the labels of t by a permutation σ conjugates the row group and the column group
of t, hence conjugates the row symmetrizer, the column antisymmetrizer, and the Young
symmetrizer:
c_{σt} = σ c_t σ⁻¹.
Consequently ℚ[Sₙ] c_{σt} = (ℚ[Sₙ] c_t) σ⁻¹, and right multiplication by σ is an isomorphism
of representations from ℚ[Sₙ] c_{σt} to ℚ[Sₙ] c_t. Since any two tableaux of the same shape
differ by a relabeling, the representation ℚ[Sₙ] c_t, and in particular its dimension and its
character, depend only on the shape of t.
Main results #
YoungTableau.youngSymmetrizer_relabel: the Young symmetrizer of a relabeled tableau is the conjugate of the Young symmetrizer, andYoungTableau.youngSymmetrizerOver_relabelsays the same for its transport to aℚ-algebra.YoungTableau.spechtIdealRelabelRepEquiv: right multiplication byσas an isomorphism of representationsℚ[Sₙ] c_{σt} ≅ ℚ[Sₙ] c_t.YoungTableau.spechtIdealRepIso,YoungTableau.finrank_spechtIdeal_eqandYoungTableau.character_spechtIdealRep_eq: the representation, its dimension, and its character depend only on the shape of the tableau.
References #
- G. D. James, The Representation Theory of the Symmetric Groups, Chapter 4.
- Schur--Weyl roadmap,
Layers 2 and 3: the Layer 3 Specht module
spechtModule μis indexed by the shapeμalone, while the Layer 2 Young symmetrizer and its left ideal are built from a tableau, so the tableau-independence proved here is what makes the Layer 3 indexing legitimate.
The row and column groups of a relabeled tableau #
Relabeling by σ conjugates the row group by σ.
Relabeling by σ conjugates the column group by σ.
A permutation preserves the rows of the relabeled tableau exactly when its conjugate preserves the rows of the original one.
Not a simp lemma: mem_rowSubgroup and rowIndex_relabel already simplify the left-hand side
past this normal form, to the pointwise condition on rows.
A permutation preserves the columns of the relabeled tableau exactly when its conjugate preserves the columns of the original one.
Not a simp lemma: mem_colSubgroup and colIndex_relabel already simplify the left-hand side
past this normal form, to the pointwise condition on columns.
The symmetrizers of a relabeled tableau #
Relabeling by σ conjugates the row symmetrizer by σ.
Relabeling by σ conjugates the column antisymmetrizer by σ; the signs are unchanged,
conjugate permutations having equal signs.
Relabeling by σ conjugates the Young symmetrizer by σ: c_{σt} = σ c_t σ⁻¹.
Relabeling by σ conjugates the transported Young symmetrizer, as it does the rational
one.
The Young-symmetrizer left ideal of a relabeled tableau #
Membership in the left ideal generated by c_{σt} is membership in the right translate by
σ⁻¹ of the left ideal generated by c_t.
Right multiplication by σ as an equivalence of left ℚ[Sₙ]-modules from ℚ[Sₙ] c_{σt} to
ℚ[Sₙ] c_t: it is right multiplication by the unit σ of the group algebra, restricted to the
two ideals.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Right multiplication by σ is an isomorphism of representations from ℚ[Sₙ] c_{σt} to
ℚ[Sₙ] c_t: being a map of left modules over the group algebra, it commutes with the action.
Equations
Instances For
The left ideals of the Young symmetrizers of a tableau and of its relabelings are isomorphic representations.
Equations
Instances For
Relabeling does not change the dimension of the Young-symmetrizer left ideal.
Relabeling does not change the character of the Young-symmetrizer left ideal.
Relabeling does not change the character of the bundled Young-symmetrizer representation.
Independence of the tableau #
The Young-symmetrizer left ideals of two tableaux of the same shape are isomorphic representations: up to isomorphism the representation depends only on the shape.
Equations
Instances For
The dimension of the Young-symmetrizer left ideal depends only on the shape of the tableau.
The character of the Young-symmetrizer left ideal depends only on the shape of the tableau.
The character of the bundled Young-symmetrizer representation depends only on the shape of the tableau.