Split exactness of the rows of the cyclic bicomplex #
In degree n, write λ for the signed cyclic operator and N = 1 + λ + ⋯ + λⁿ.
When n + 1 is invertible in the commutative coefficient semiring, averaging gives a projection
P = N / (n + 1) onto the cyclic cochains. The operator
H = (∑ j ≤ n, ∑ k < j, λᵏ) / (n + 1) satisfies
(1 - λ) H = H (1 - λ) = 1 - P.
Consequently the row alternating between 1 - λ and N is exact at both kinds
of terms: range N = ker (1 - λ) and range (1 - λ) = ker N.
These explicit splittings are used to compare the cyclic cochain complex with
the total cyclic bicomplex. No multiplication or unit on the argument module is
needed for these horizontal identities.
References #
- A. Connes, Noncommutative Geometry, Chapter III, §1.
- J.-L. Loday, Cyclic Homology, §2.1.
Averaging over cyclic rotations projects onto the cyclic cochains.
Instances For
The cyclic average is the cyclic norm divided by the number of arguments.
Averaging takes values in the cyclic cochains.
Averaging fixes every cyclic cochain.
The cyclic average is idempotent.
The cyclic average is an idempotent endomorphism.
The cyclic average absorbs itself under composition.
The cyclic average absorbs the cyclic operator on the left: λ P = P.
The cyclic average absorbs the cyclic operator on the right: P λ = P.
Averaging and the cyclic norm have the same kernel.
The image of averaging is exactly the cyclic cochains.
The cyclic row homotopy. Its product with 1 - λ on either side is 1 - P,
where P is cyclic averaging.
Instances For
The explicit finite-sum formula for the cyclic row homotopy.
The row homotopy splits 1 - λ on the left, up to the cyclic projection.
The row homotopy splits 1 - λ on the right, up to the cyclic projection.
Applying the row homotopy gives a preimage of φ - P φ under 1 - λ.
The cyclic norm surjects onto the cyclic cochains.
Exactness of a cyclic-bicomplex row at a term following N.
Exactness of a cyclic-bicomplex row at a term following 1 - λ.
For a cochain killed by N, the row homotopy gives an explicit preimage.