Factoring a product of conjugate primes in a Dedekind domain #
Let R be a Dedekind domain carrying a ring endomorphism σ, and let S be a finite set of
nonzero primes of R on which σ acts involutively. This file characterizes the ideals A with
A * σ A = ∏ p ∈ S, p as exactly the products over the transversals of σ on S. When σ
additionally has no fixed points on S, so that S splits into conjugate pairs {p, σ p}, it
also proves that there are exactly 2 ^ (#S / 2) such ideals, one for each choice of a prime from
each conjugate pair. Fixed-point-freeness is needed only for this count.
The count is what makes such factorizations a source of many ideals with a prescribed conjugate
product: taking S to be a set of primes above rational primes that split into conjugate pairs,
the theorem produces exactly 2 ^ (#S / 2) ideals A with A · σA the prescribed ideal. The
argument is the interplay of two facts: a divisor of a product of distinct primes is the product
of a subset of them (TauCeti.exists_subset_finset_prod_eq_of_dvd), and the
transversals of a fixed-point-free involution are counted by
TauCeti.ncard_setOf_isInvolutionTransversal.
References #
The existence half of the count is exists_transversal_family in the formalization
kim-em/erdos-unit-distance, written for
Alpöge's disproof of the uniform-constant Erdős unit-distance conjecture, where it is stated as
the lower bound 2 ^ (#S / 2) ≤ #G for a family G of such ideals. The induction on S that
strips off one conjugate pair at a time is taken from there; it is carried out here on the
transversals rather than on the ideals, which turns the bound into the exact count and separates
the combinatorics from the arithmetic.
Main results #
TauCeti.mul_map_eq_prod_iff:A * σ A = ∏ p ∈ S, pexactly whenAis the product over a transversal ofσonS.TauCeti.ncard_setOf_mul_map_eq_prod: there are exactly2 ^ (#S / 2)suchA.
The conjugate factorizations of a product of paired primes. If a ring endomorphism σ
acts involutively on a finite set S of nonzero primes, then the ideals A with
A * σ A = ∏ p ∈ S, p are exactly the products over the transversals of σ on S.
The conjugate factorization count. If a ring endomorphism σ acts involutively and
without fixed points on a finite set S of nonzero primes, then there are exactly 2 ^ (#S / 2)
factorizations A * σ A = ∏ p ∈ S, p, one for each choice of a prime from each conjugate
pair.