Idempotents modulo an ideal in the Jacobson radical #
In any ring, an idempotent e in the Jacobson radical is zero: 1 - e has a left inverse and
(1 - e) e = 0. Consequently, in a commutative ring, idempotents are determined by their
residues modulo any ideal I contained in the Jacobson radical. If e and e' are idempotents
with e - e' in I, then e (1 - e') and (1 - e) e' are idempotents in the Jacobson radical,
hence zero, and e - e' = e (1 - e') - (1 - e) e' = 0.
This is the uniqueness half of lifting idempotents along a Henselian pair, and it needs no
Henselian hypothesis. The second step needs commutativity: for example, in the upper triangular
2 × 2 matrices over a field, E₁₁ and E₁₁ + E₁₂ are distinct idempotents whose difference
lies in the Jacobson radical.
Main results #
IsIdempotentElem.eq_zero_of_mem_jacobson_bot: an idempotent in the Jacobson radicalIdeal.jacobson ⊥of a not necessarily commutative ring is zero.Ideal.Quotient.isIdempotentElem_mk_iff:ais idempotent moduloIif and only ifa * a - a ∈ I.IsIdempotentElem.eq_of_sub_mem_of_le_jacobson_bot: idempotents congruent modulo an ideal in the Jacobson radical are equal.Ideal.injOn_quotient_mk_isIdempotentElem: modulo an ideal in the Jacobson radical, the quotient map is injective on idempotents.IsIdempotentElem.exists_smul_eq_mul_of_mul_sub_smul_mem: in a module-finiteS-algebraT, an idempotentewithe T ⊆ S e + JT, forJin the Jacobson radical ofS, hase T = S e.
References #
- Stacks Project, Lemma 15.11.6, the uniqueness of lifts in condition (3).
- Ported from T. Dupuy, T. Tucker and Z. Wang,
pcfawd-formalization at commit
a39c3781b9850b9f3d5cbc9920322a3b8e365ef2(Apache-2.0),lean/Pcf/Stacks/Purity/HenselianIdempotents.lean:eq_zero_of_mem_jacobson_botandeq_of_sub_mem_of_le_jacobson_botare itsPcf.Stacks.isIdempotentElem_eq_zero_of_mem_jacobsonandPcf.Stacks.eq_of_isIdempotentElem_of_sub_mem_of_le_jacobson, andinjOn_quotient_mk_isIdempotentElemrestates asSet.InjOnthe injectivity step of itsPcf.Stacks.bijective_idempotentQuotientMap_of_henselian.
An idempotent in the Jacobson radical Ideal.jacobson ⊥ of a (not necessarily commutative)
ring is zero.
An element is idempotent modulo a two-sided ideal I if and only if a * a - a ∈ I.
Idempotent lifts are unique modulo the Jacobson radical. Idempotents that are congruent modulo an ideal contained in the Jacobson radical are equal.
Modulo an ideal in the Jacobson radical, the quotient map is injective on idempotents.
Nakayama's lemma for an idempotent. Let T be a module-finite S-algebra and J an
ideal of S in the Jacobson radical. If an idempotent e of T satisfies e T ⊆ S e + JT, then
e T = S e.