Orders in finite-dimensional algebras #
Let R be a domain with fraction field F and E a finite-dimensional F-algebra, not
necessarily commutative. An R-order in E is an R-subalgebra Λ of E which is an R-lattice
in E in the sense of Submodule.IsLattice: it is finitely generated as an R-module and spans
E over F. Orders are the integral structures on which arithmetic of E is done: the ring of
integers of a number field, group rings R[G] ⊆ F[G], and M_n(R) ⊆ M_n(F) are orders.
Every element of an order is integral over R. Conversely, over an integrally closed noetherian
R, a spanning subalgebra all of whose elements are integral is an order provided the regular trace
form of E is nondegenerate: the regular traces of products of its elements lie in R, so the
subalgebra lies in the R-span of the dual basis of an F-basis chosen inside it. Some hypothesis
of this kind is needed: if R is not a field, then in E = F[ε]/(ε²) the subalgebra R + F ε
spans E and consists of integral elements, but is not finitely generated over R. The
regular-trace hypothesis is stronger than necessary: it excludes M_p(F) in characteristic p,
whose regular trace form vanishes, although the conclusion holds there via the reduced trace.
Main definitions #
TauCeti.IntegralOrder.IsOrder F Λ: theR-subalgebraΛofEis anR-order inE.TauCeti.IntegralOrder.groupRingSubalgebra R F G: the group ringR[G]as anR-subalgebra ofF[G].
Main results #
TauCeti.IntegralOrder.isOrder_iff:Λis an order iff it is finite overRand spansE.TauCeti.IntegralOrder.isOrder_op_iff:Λᵒᵖis an order inEᵐᵒᵖiffΛis an order inE.TauCeti.IntegralOrder.IsOrder.isIntegral: every element of an order is integral overR.TauCeti.IntegralOrder.IsOrder.le_integralClosure: in a commutative algebra, every order lies in the integral closure ofR.TauCeti.IntegralOrder.toSubmodule_le_dualSubmodule_regularTraceForm: over an integrally closedR, a subalgebra of integral elements lies in its own dual for the regular trace form.TauCeti.IntegralOrder.toSubmodule_le_span_dualBasis: such a subalgebra containing anF-basisbofElies in theR-span of the regular-trace dual basis ofb.TauCeti.IntegralOrder.isOrder_of_isIntegral: a spanning subalgebra of integral elements is an order whenRis integrally closed and noetherian and the regular trace form is nondegenerate.TauCeti.IntegralOrder.mem_groupRingSubalgebra:x ∈ F[G]lies inR[G]iff all its coefficients come fromR.TauCeti.IntegralOrder.groupRing_isOrder:R[G]is an order inF[G]for a finite monoidG.TauCeti.IntegralOrder.integralClosure_isOrder: the integral closure of an integrally closed noetherianRin a finite separable extension ofFis an order.
References #
- H. Johnston, Notes on Galois modules, Definition 3.8 and Examples 3.10.
- J. Voight, Quaternion algebras, Definition 10.2.1 and Lemma 10.3.7; the integrality criterion is proved there for separable algebras with the reduced trace, and here with the regular trace.
TauCeti.IntegralOrder.toSubmodule_le_span_dualBasis and the proof of
TauCeti.IntegralOrder.isOrder_of_isIntegral follow Mathlib's
IsIntegralClosure.range_le_span_dualBasis and IsIntegralClosure.isNoetherian, which carry out
the dual-basis bound for the integral closure in a finite separable field extension.
An R-subalgebra Λ of an F-algebra E is an R-order in E if it is an R-lattice in
E: finitely generated as an R-module, with F-span all of E.
Instances For
Being an order is being an R-lattice in E (this is the definition of IsOrder).
An R-subalgebra is an order exactly when it is finite over R and spans E over F.
An order is finite as an R-module.
An order spans its ambient algebra over F.
Elements of orders are integral. Every element of an R-order is integral over R, since
the order is a finitely generated R-module.
A finitely generated subalgebra containing an order is an order.
Opposite orders. Λᵒᵖ is an R-order in Eᵐᵒᵖ exactly when Λ is an R-order in E.
In a commutative algebra, every R-order lies in the integral closure of R.
Integral subalgebras lie in their own trace dual. If every element of the R-subalgebra Γ
is integral over the integrally closed domain R, then the regular trace Tr_F (x * y) of a
product of two elements of Γ lies in R: Γ lies in its dual for the regular trace form.
The trace-dual bound. Let R be integrally closed and let b be an F-basis of E lying
in an R-subalgebra Γ of integral elements. Then Γ lies in the R-span of the basis dual to
b for the (nondegenerate) regular trace form. The bound depends only on b, so it holds
simultaneously for every such Γ containing b.
Integral spanning subalgebras are orders. Let R be an integrally closed noetherian domain
with fraction field F, and E a finite-dimensional F-algebra whose regular trace form
(x, y) ↦ Tr_F (x * y) is nondegenerate. An R-subalgebra of E spanning E over F and
consisting of elements integral over R is an R-order in E.
Integral closures are orders. The integral closure of an integrally closed noetherian domain
R in a finite separable extension L of its fraction field F is an R-order in L.
The group ring R[G] as an R-subalgebra of F[G]: the image of the map R[G] → F[G]
applying algebraMap R F to every coefficient.
Instances For
An element of F[G] lies in R[G] exactly when all its coefficients come from R.
As an R-module, R[G] is spanned by the basis elements g of F[G].