The conormal sequence of a formally smooth quotient #
Let P → S be a surjection of R-algebras with kernel I. The conormal sequence
I/I² → S ⊗[P] Ω[P⁄R] → Ω[S⁄R] → 0
is exact (KaehlerDifferential.exact_kerCotangentToTensor_mapBaseChange). If S is formally
smooth over R, the identity of S lifts along the square-zero extension P/I² → S, and such a
section is the same as a retraction of I/I² → S ⊗[P] Ω[P⁄R]
(retractionKerCotangentToTensorEquivSection). So the first map is injective, and the sequence is
exact on the left as well. If S is moreover formally unramified, then Ω[S⁄R] = 0 and the
conormal module I/I² is identified with S ⊗[P] Ω[P⁄R].
For a closed point of a scheme over a field whose residue field is separable over the base, this
identifies the Zariski cotangent space 𝔪/𝔪² with the fibre of the differentials.
Main results #
KaehlerDifferential.kerCotangentToTensor_injective_of_formallySmooth: the conormal mapI/I² → S ⊗[P] Ω[P⁄R]is injective whenSis formally smooth overR.KaehlerDifferential.kerCotangentToTensor_bijective_of_formallyEtale: it is bijective whenSis formally étale overR.
References #
- Stacks Project, Tag 031I: a quotient
P/Iis formally smooth exactly when the conormal sequence is split exact on the left, givenPformally smooth. Only the implication from formal smoothness to injectivity is used here, and it needs no hypothesis onP.
For a surjection P → S with kernel I onto a formally smooth R-algebra, the conormal map
I/I² → S ⊗[P] Ω[P⁄R] is injective.
For a surjection P → S with kernel I onto a formally étale R-algebra, the conormal map
I/I² → S ⊗[P] Ω[P⁄R] is bijective.