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TauCeti.RingTheory.LocalRing.Quotient

The maximal ideal and the cotangent space of a quotient of a local ring #

Let π : Q → A be a surjective homomorphism of local rings. Then π maps 𝔪_Q onto 𝔪_A, and an element of Q maps into 𝔪_A² exactly when it lies in ker π + 𝔪_Q². Consequently lifts to Q of a basis of the cotangent space 𝔪_A / 𝔪_A² span 𝔪_Q modulo ker π + 𝔪_Q², and they are linearly independent modulo it.

For a local homomorphism R → S with S local and an ideal J of R, the induced map R ⧸ J → S ⧸ J S is again local. Dividing both sides of a local homomorphism by an ideal of the base, as in inductions on the dimension of the base, therefore stays among local homomorphisms. When J is the maximal ideal of R and generates the maximal ideal of S, this map is the residue field extension, whose degree is then the rank of a finite free S.

Main results #

Along a surjective homomorphism of local rings π : Q → A, an element a maps into 𝔪_A² if and only if it lies in ker π + 𝔪_Q².

Along a surjective homomorphism of local rings π : Q → A with ker π ≤ 𝔪_Q², the maximal ideal of A is not principal as soon as no single element of 𝔪_Q spans 𝔪_Q modulo 𝔪_Q²: a generator π z of 𝔪_A would give 𝔪_Q ≤ (z) + ker π ≤ (z) + 𝔪_Q².

If the maximal ideal of Q is J + (yⱼ), then the images of the yⱼ generate the maximal ideal of the local ring Q ⧸ J.

Lifts of a basis of the cotangent space of a quotient. Let π : Q → A be a surjective homomorphism of local rings, where 𝔪_Q is finitely generated. Then there are lifts y : Fin e → Q of a basis of 𝔪_A / 𝔪_A², where e is its dimension. They lie in 𝔪_Q, span 𝔪_Q modulo ker π + 𝔪_Q², and are linearly independent modulo it: a combination ∑ cⱼ yⱼ lies in ker π + 𝔪_Q² only if every cⱼ ∈ 𝔪_Q.

For a local homomorphism R → S to a local ring and an ideal J of R, the induced homomorphism R ⧸ J → S ⧸ J S is local. The ring R need not be local.

Residue degree of a finite free extension in which the maximal ideal stays maximal. If S is a finite free extension of the local ring R and the maximal ideal of R generates the maximal ideal of S, then the residue field extension has degree [S : R].

The proof is adapted from that of Mathlib's IsLocalRing.finrank_eq_finrank_residueField, the étale special case, and goes through Mathlib's IsLocalRing.finrank_quotient_map.