Monic irreducible polynomials of a fixed degree #
The monic irreducible polynomials of a given degree over a semiring R form a set depending
only on R and the degree. When R is finite that set is finite, because a monic polynomial of
degree d is determined by its lower coefficients: Polynomial.monicEquivDegreeLT matches such
polynomials with Polynomial.degreeLT, which Polynomial.degreeLTEquiv identifies with the
finite function space Fin d → R.
Main definitions #
Polynomial.monicIrreduciblesOfDegree: the monic irreducible polynomials of degreed.
Main results #
Polynomial.mem_monicIrreduciblesOfDegree_iff: the defining membership condition.Polynomial.finite_monicIrreduciblesOfDegree: over a finite coefficient ring there are finitely many.Polynomial.ncard_monicIrreduciblesOfDegree_one: over a domain the monic irreducibles of degree one are theX - C a, as many as the elements of the coefficient ring.TauCeti.irreducible_map_intCast_of_natDegree_eq_three: a monic integral cubic with no integral root is irreducible overℚ.TauCeti.irreducible_map_intCast_of_natDegree_eq_four: a monic integral quartic with no integral root and no monic integral quadratic factor is irreducible overℚ.
The monic irreducible polynomials of degree d over R.
The set depends only on R and d, which is what lets a counting argument compare it with an
unrelated family without assuming a bound on either.
Equations
- Polynomial.monicIrreduciblesOfDegree R d = {g : Polynomial R | g.Monic ∧ Irreducible g ∧ g.natDegree = d}
Instances For
Membership in monicIrreduciblesOfDegree is the conjunction defining it.
Over a finite coefficient ring there are finitely many monic irreducibles of each degree. They sit inside the monic polynomials of that degree, which are parametrised by their lower coefficients.
Over a domain there are as many monic irreducible polynomials of degree one as elements of the coefficient ring.
A monic integral cubic without an integral root is irreducible over ℚ: a rational root of
a monic integral polynomial is integral.
A monic integral quartic with no integral root and no monic integral quadratic factor is
irreducible over ℚ. By Gauss's lemma it suffices to rule out monic factors of degree one and two
over ℤ, and a monic linear factor X + C c divides g exactly when -c is a root of g.