Geometrically regular algebras over a field #
An algebra B over a field k is geometrically regular if B is Noetherian and the base
change L ⊗[k] B is a regular ring for every finite purely inseparable extension L / k
(Stacks, Definition 10.166.2, in the form of Lemma 10.166.1). Stacks, Lemma 10.166.1, shows that
this is equivalent to regularity of L ⊗[k] B for every finitely generated field extension
L / k; that equivalence is not proved here. Geometric regularity of the fibres is the condition
defining regular ring maps, G-rings and excellent rings.
Regularity of B itself does not suffice: a nontrivial finite purely inseparable extension L / k
is a field, hence regular, but L ⊗[k] L is not reduced, so L is not geometrically regular over
k.
Main definitions and results #
TauCeti.Excellence.GeometricallyRegular k B:Bis a geometrically regulark-algebra.TauCeti.Excellence.GeometricallyRegular.isRegularRing: a geometrically regular algebra is a regular ring.TauCeti.Excellence.GeometricallyRegular.isRegularRing_tensorProduct': the base change to a finite purely inseparable extension in any universe is a regular ring.AlgEquiv.geometricallyRegular: geometric regularity is invariant under isomorphisms ofk-algebras.TauCeti.Excellence.GeometricallyRegular.of_smooth: a smoothk-algebra is geometrically regular; this coverskitself, the zero algebra and polynomial rings in finitely many variables.TauCeti.Excellence.GeometricallyRegular.of_isSeparable: a finite separable field extension is geometrically regular.TauCeti.Excellence.GeometricallyRegular.surjective_algebraMap_of_algHom: a nonzero geometrically regulark-algebra receives nok-algebra map from a nontrivial finite purely inseparable extension ofk.TauCeti.Excellence.geometricallyRegular_iff_isSeparable: a finite purely inseparable extension is geometrically regular exactly when it is separable, that is, trivial.TauCeti.Excellence.geometricallyRegular_tensorProduct_iff_of_bijective: geometric regularity is unchanged by base change along an isomorphism of fieldsk → K.TauCeti.Excellence.GeometricallyRegular.of_isLocalization: a localization of a field is geometrically regular.TauCeti.Excellence.not_geometricallyRegular_trivSqZeroExt: the dual numbersk[ε]/(ε²)are not geometrically regular.
References #
- The Stacks Project, Section 10.166 (Geometrically regular algebras), Lemma 10.166.1 and Definition 10.166.2.
An algebra B over a field k is geometrically regular if B is Noetherian and
L ⊗[k] B is a regular ring for every finite purely inseparable field extension L / k
(Stacks, Definition 10.166.2, in the form of Lemma 10.166.1). The extensions L range over the
universe of k; GeometricallyRegular.isRegularRing_tensorProduct' removes that restriction.
- isNoetherianRing : IsNoetherianRing B
A geometrically regular algebra is Noetherian.
- isRegularRing_tensorProduct (L : Type u) [Field L] [Algebra k L] [Module.Finite k L] [IsPurelyInseparable k L] : IsRegularRing (TensorProduct k L B)
The base change of a geometrically regular algebra to a finite purely inseparable extension of the base field is a regular ring.
Instances
A geometrically regular algebra is a regular ring: take L = k.
The extensions L in the definition range over the universe of k, but the base change to a
finite purely inseparable extension L / k in any universe is a regular ring: L has a copy
Shrink L in the universe of k.
A smooth algebra over a field is geometrically regular: its base change to any field is smooth over that field, hence regular.
A finite separable field extension is geometrically regular, being étale over the base.
A nonzero geometrically regular k-algebra B receives no k-algebra map from a nontrivial
finite purely inseparable extension L / k: if f : L →ₐ[k] B exists, then L = k. Indeed
L ⊗[k] L embeds into the regular, hence reduced, ring L ⊗[k] B.
A finite purely inseparable extension L / k is geometrically regular if and only if it is
separable, that is, if and only if L = k.
The dual numbers k[ε]/(ε²) over a field k are not geometrically regular: they are not even
reduced.
Geometric regularity does not see an isomorphism of base fields: if algebraMap k K is
bijective, then K ⊗[k] B is geometrically regular over K if and only if B is geometrically
regular over k.
A localization of a field k is geometrically regular over k: it is either zero or k
itself, and in both cases smooth over k.