Cancelling a regular summand of S² #
Let S be a semisimple ring. If v : S² generates a copy of the regular module, that is, if
x ↦ x v is injective on S, then the quotient S² / S v is again isomorphic to S. The
submodule S v has a complement Q because every module over a semisimple ring is semisimple, so
that S × Q ≃ S × S; since S has finite length as a module over itself, the Krull–Schmidt
cancellation theorem gives Q ≃ S. For the group algebra k[G] of a finite group over a field
in which #G is invertible, the semisimplicity is Maschke's theorem.
The second result applies this after a flat base change. Let A be an algebra over a commutative
ring R, and Q a flat R-algebra such that A ⊗[R] Q is semisimple — A = ℤ_p[G] and
Q = ℚ_p for a finite group G, say. If v : A² generates a copy of A, then the base change
(A² / A v) ⊗[R] Q is isomorphic to A ⊗[R] Q as a left A-module: tensoring is right exact,
so the base change of A² / A v is (A ⊗[R] Q)² / (A ⊗[R] Q) v, and flatness carries the
injectivity of x ↦ x v to A ⊗[R] Q, where the first result applies.
Main statements #
TauCeti.nonempty_quotient_span_singleton_linearEquiv_of_injective: over a semisimple ring, the quotient ofS²by an injectively generated singleton relation is linearly equivalent toS.TauCeti.nonempty_quotient_span_singleton_tensor_linearEquiv_of_injective: the base change ofA² / A valong a flatR-algebraQwithA ⊗[R] Qsemisimple isA ⊗[R] Q.
Let S be a semisimple ring. If the singleton relation generated by v : S² is a copy of the
regular module, then its quotient is also linearly equivalent to the regular module.
Cancelling a regular summand after a flat base change. Let A be an algebra over the
commutative ring R, and Q a flat R-algebra such that A ⊗[R] Q is a semisimple ring. If
v : A² generates a copy of A, then the base change (A² ⧸ A v) ⊗[R] Q is isomorphic to
A ⊗[R] Q as a left A-module.