Linear forms over a separable extension, through the trace #
Let L / K be a finite separable field extension and V a vector space over L. Composing an
L-linear form on V with the trace Tr_{L/K} : L → K gives a K-linear form on V, and every
K-linear form on V arises this way from exactly one L-linear form. This is the
nondegeneracy of the trace form, traceForm_nondegenerate, applied pointwise: the L-linear
form attached to μ sends v to the element of L which the trace form pairs with
b ↦ μ (b • v).
This is how Weil differentials of a function field are transported along an extension of the constant field: they are linear forms over the constant field, and the trace form of the constant-field extension converts linear forms over the larger constant field to linear forms over the smaller one.
Main definitions #
Module.Dual.traceCompEquiv: theK-linear equivalenceModule.Dual L V ≃ₗ[K] Module.Dual K V,φ ↦ Tr_{L/K} ∘ φ.
Main results #
Module.Dual.traceCompEquiv_apply: the equivalence composes with the trace.Module.Dual.apply_eq_zero_iff_forall_trace_eq_zero: anL-linear form vanishes atvexactly when the traces of its values on theL-line throughvall vanish.
References #
- H. Stichtenoth, Algebraic Function Fields and Codes, 2nd ed., GTM 254, Springer, 2009, proof of Theorem 3.4.6, where this identification converts the trace of a Weil differential into a Weil differential over the larger constant field.
Linear forms over a finite separable extension, through the trace: composition with
Tr_{L/K} identifies the L-linear forms on an L-vector space with its K-linear forms.
Equations
- One or more equations did not get rendered due to their size.
Instances For
The equivalence traceCompEquiv composes a linear form with the trace.
The L-linear form attached to a K-linear form μ has trace μ.
An L-linear form vanishes at v exactly when the traces of its values at the multiples
b • v all vanish.