Valuations trivial on a base ring #
A valuation trivial on a base ring stays trivial on that base when restricted along a map of algebras over it. The restriction changes where the valuation is evaluated but not what it does to constants, because an algebra map fixes them.
A valuation trivial on a base ring also sees the base as scalars of size one, so a family of elements with pairwise distinct nonzero valuations is linearly independent over the base: in a linear combination with a nonzero coefficient, the summand of largest valuation dominates and the combination cannot vanish.
Main results #
Valuation.IsTrivialOn.comap: restriction preserves triviality on the base, for a valuation on any algebra restricted along any algebra map over that base.Valuation.linearIndependent_of_injective: elements of pairwise distinct nonzero valuations are linearly independent over a base ring on which the valuation is trivial.
References #
- T. Wedhorn, Adic Spaces, for valuations, their restriction along a ring map, and triviality on a base ring.
Restricting a valuation along an algebra map preserves triviality on the base. An algebra map fixes the base, so the restricted valuation takes the same values on constants.
Elements of pairwise distinct nonzero valuations are linearly independent over a base ring on which the valuation is trivial. A nontrivial linear combination has, among its summands with nonzero coefficient, a unique one of largest valuation, and that summand dictates the valuation of the sum, which is therefore nonzero.