The canonical characters of the Demushkin normal forms #
Labute's classification attaches to a Demushkin group G its canonical character, the unique
continuous χ : G → ℤ_pˣ with the prescription property (TauCeti.HasPrescriptionProperty): every
reduction H¹(G, I(χ)/pⁱ) → H¹(G, I(χ)/p) of the twisted coefficients is surjective. This file
computes that character on each of the normal-form presentations of
TauCeti.Topology.Algebra.Group.Profinite.Demushkin.NormalForm.Basic and on the presentation by
the even dyadic word with a 2-adic exponent of
TauCeti.Topology.Algebra.Group.Profinite.Demushkin.NormalForm.Two.Even.PadicExponent.Basic,
proving Labute's Theorem 4 for the presented groups: each normal form has exactly one continuous
character with the prescription property, the standard orientation of
TauCeti.Topology.Algebra.Group.Profinite.Demushkin.NormalForm.Orientation, whose values on the
generators are
q ≠ 2, relatorx₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n):χ(x₂) = (1 - q)⁻¹, all otherχ(x_i) = 1;q = 2,nodd, relatorx₁² x₂^{2^f} (x₂, x₃) ⋯ (x_{n-1}, x_n):χ(x₁) = -1,χ(x₃) = (1 - 2^f)⁻¹, all otherχ(x_i) = 1; at levelf = ∞, on the relatorx₁² (x₂, x₃) ⋯ (x_{n-1}, x_n),χ(x₁) = -1and all otherχ(x_i) = 1;q = 2,neven, relatorx₁^{2+α} (x₁, x₂) x₃^q (x₃, x₄) ⋯ (x_{n-1}, x_n)with a2-adic exponentαand tail exponentq:χ(x₂) = -(1 + α)⁻¹,χ(x₄) = (1 - q)⁻¹whenever the factorx₃^qis present (2 < n), all otherχ(x_i) = 1; the natural-exponent relatorx₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n)is the caseα = a,q = 2^f, withχ(x₂) = -(1 + a)⁻¹andχ(x₄) = (1 - 2^f)⁻¹; in rank two, on the wordx₁^{2+a} (x₁, x₂)with no level,χ(x₁) = 1andχ(x₂) = -(1 + a)⁻¹.
The values are stated as equations in ℤ_p, χ(x₂) (1 - q) = 1 and so on, so that no inverse has
to be formed to state them.
The proof is the forced computation on a derivation. For a presented pro-p group the
prescription property of χ says that every continuous crossed homomorphism F of the free
group for χ ∘ mk, a continuous F with F (x * y) = χ x * F y + F x, kills the relator
(TauCeti.presentedProP.hasPrescriptionProperty_iff_forall_isCrossedHom_eq_zero). On a relator
word, F is computed from F (x ^ k) = (1 + χ x + ⋯ + χ x ^ (k-1)) F x and
χ x * χ y * F (x, y) = (1 - χ y) F x + (χ x - 1) F y on Labute's commutator (x, y) = x⁻¹y⁻¹xy:
its value is an ℤ_p-linear form in the values F (x_i), with coefficients polynomial in the
χ(x_i). Since F takes any prescribed values on the generators, the form must vanish
identically. Reading off its coefficients, one generator at a time, forces the values of χ
above: the commutator factor (x_a, x_b) containing x_j gives χ(x_b) = 1 or χ(x_a) = 1, and
the generator carrying the p-th power gives the equation q + χ(x₂)⁻¹ - 1 = 0, respectively
1 + χ(x₁) = 0 or 2 + a + χ(x₂)⁻¹ - 1 = 0. Conversely, at the tabulated values the form
vanishes, so the standard orientation has the prescription property.
Main results #
TauCeti.IsCrossedHom.mul_mul_map_labuteComm: the value of a crossed homomorphism on Labute's commutator;TauCeti.IsCrossedHom.map_demushkinWordNeTwo,TauCeti.IsCrossedHom.map_demushkinWordTwoOdd,TauCeti.IsCrossedHom.map_demushkinWordTwoEven,TauCeti.IsCrossedHom.map_demushkinWordTwoRankTwo,TauCeti.IsCrossedHom.map_demushkinWordTwoOddTop: its value on the five normal-form words;TauCeti.IsCrossedHom.map_demushkinWordTwoEvenPadic: its value on the even dyadic word with a2-adic exponent;TauCeti.IsCrossedHom.map_demushkinWordNeTwo_eq_zero: at the tabulated character values theq ≠ 2word is killed, on any tuple.TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordNeTwo_iff,TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoOdd_iff,TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoEven_iff,TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoRankTwo_iff,TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoOddTop_iff,TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoEvenPadic_iff: a continuous character of a normal-form presentation has the prescription property exactly when it takes the tabulated values; the_of_apply_eqversions are the existence halves, without the minimality and rank hypotheses. The two theorems for the even dyadic word with natural exponent are the caseα = a,q = 2^fof those for the word with a2-adic exponent.TauCeti.hasPrescriptionProperty_orientationNeTwo,TauCeti.hasPrescriptionProperty_orientationTwoOdd,TauCeti.hasPrescriptionProperty_orientationTwoEven,TauCeti.hasPrescriptionProperty_orientationTwoRankTwo,TauCeti.hasPrescriptionProperty_orientationTwoOddTop: the standard orientations have the prescription property;TauCeti.eq_orientationNeTwo_of_hasPrescriptionProperty,TauCeti.eq_orientationTwoOdd_of_hasPrescriptionProperty,TauCeti.eq_orientationTwoEven_of_hasPrescriptionProperty,TauCeti.eq_orientationTwoRankTwo_of_hasPrescriptionProperty,TauCeti.eq_orientationTwoOddTop_of_hasPrescriptionProperty: a character with the prescription property is the orientation with its own marked values.TauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordNeTwo,TauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordTwoOdd,TauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordTwoEven,TauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordTwoRankTwo,TauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordTwoOddTop: each normal form has exactly one continuous character with the prescription property; for the odd word atf = ∞this holds in every odd rank, including rank one. For the even dyadic word with a2-adic exponent, the orientation and the uniqueness statement are inTauCeti.Topology.Algebra.Group.Profinite.Demushkin.NormalForm.Two.Even.PadicExponent.Character.TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoOdd_one_iffandTauCeti.existsUnique_hasPrescriptionProperty_presentedProP_demushkinWordTwoOdd_one: in rank one, where the odd word readsx₁²and the group isℤ/2, the prescription property meansχ(x₁) = -1, and the sign character is the unique character with it.
References #
- J. P. Labute, Classification of Demushkin groups, Canad. J. Math. 19 (1967), 106–132, §2, Proposition 6 and Theorem 4, and Remark 2.
- J.-P. Serre, Structure de certains pro-p-groupes, Séminaire Bourbaki 252 (1962/63).
Crossed homomorphisms on Labute's commutator and on the normal-form words #
The value of a crossed homomorphism on Labute's commutator (x, y) = x⁻¹y⁻¹xy, multiplied
through by χ x * χ y: it is read off F (x * y) = F (y * x * (x, y)).
A crossed homomorphism vanishing at x and y vanishes at (x, y).
A crossed homomorphism vanishes at (x, y) when the character is trivial at x and y.
If a crossed homomorphism takes the value 1 at x, the value 0 at y and vanishes at
(x, y), then the character is trivial at y.
If a crossed homomorphism takes the value 0 at x, the value 1 at y and vanishes at
(x, y), then the character is trivial at x.
The value of a crossed homomorphism on a product of Labute commutators indexed by
List.range m is the sum of the values on the factors.
For n even and a crossed homomorphism F with F (x_i) = δ_{ij} for some 2 ≤ j < n, only
the factor containing x_j contributes to the sum of its values on the commutators
(x₃, x₄), …, (x_{n-1}, x_n) (the 0-based pairs (x (2i+2), x (2i+3)) for i < n / 2 - 1): the
sum is the value on the factor (x (2 ((j-2)/2) + 2), x (2 ((j-2)/2) + 3)).
For a crossed homomorphism F with F (x_i) = δ_{ij} for some j < 2, the sum of its values
on the commutators (x₃, x₄), …, (x_{n-1}, x_n) (the 0-based pairs (x (2i+2), x (2i+3)) for
i < n / 2 - 1) is 0.
The value of a crossed homomorphism on the q ≠ 2 normal-form word
x₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n).
A crossed homomorphism kills the q ≠ 2 word at the tabulated character values. For
n ≥ 2 and a tuple x with χ (x 1) * (1 - q) = 1 and χ (x i) = 1 for i ≠ 1 (the 0-based
indices of the tuple: χ(x₂) = (1 - q)⁻¹ and χ(x_i) = 1 for i ≠ 2), the value of a crossed
homomorphism F on x₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n) is (q + χ(x₂)⁻¹ - 1) F (x₁) = 0.
The value of a crossed homomorphism on the q = 2, n odd normal-form word
x₁² x₂^{2^f} (x₂, x₃)(x₄, x₅) ⋯ (x_{n-1}, x_n).
The value of a crossed homomorphism on the q = 2, n odd normal-form word at level
f = ∞, x₁² (x₂, x₃)(x₄, x₅) ⋯ (x_{n-1}, x_n).
The value of a crossed homomorphism on the q = 2, n even normal-form word
x₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n).
A crossed homomorphism kills the q = 2, n even word at the tabulated character values.
For n ≥ 4 and a tuple x with χ (x 1) * (1 + a) = -1, χ (x 3) * (1 - 2^f) = 1 and
χ (x i) = 1 for i ≠ 1, 3 (the 0-based indices of the tuple: χ(x₂) = -(1 + a)⁻¹,
χ(x₄) = (1 - 2^f)⁻¹ and χ(x_i) = 1 otherwise), the value of a crossed homomorphism F on
x₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n) is
(2 + a + χ(x₂)⁻¹ - 1) F (x₁) + (2^f + χ(x₄)⁻¹ - 1) F (x₃) = 0.
The value of a crossed homomorphism on the rank-two q = 2 normal-form word
x₁^{2+a} (x₁, x₂).
Crossed homomorphisms on the even dyadic word with a 2-adic exponent #
The value of a crossed homomorphism on the word
x₁^{2+α} (x₁, x₂) x₃^q (x₃, x₄) ⋯ (x_{n-1}, x_n), with the 2-adic power x₁^{2+α} kept as a
single letter.
For n even and a continuous crossed homomorphism F with F (x_i) = δ_{ij} for some
3 ≤ j < n (so x_j is x₄ or a later generator) which kills the word
x₁^{2+α} (x₁, x₂) x₃^q (x₃, x₄) ⋯ (x_{n-1}, x_n), the value of F on the commutator factor
containing x_j is 0.
The q ≠ 2 normal form #
The tabulated values give the prescription property, q ≠ 2 (Labute, Theorem 4,
existence). A continuous character of the pro-p group presented by
x₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n) with χ(x₂) (1 - q) = 1 and χ(x_i) = 1 for i ≠ 2 has
the prescription property: on the relator, every crossed homomorphism for χ ∘ mk takes the value
(q + χ(x₂)⁻¹ - 1) F(x₁) = 0.
The prescription property forces the tabulated values, q ≠ 2 (Labute, Theorem 4, the
forced computation on a derivation). For p ∣ q and n ≥ 2 even, a continuous character of the
pro-p group presented by x₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n) has the prescription property
exactly when χ(x₂) (1 - q) = 1 and χ(x_i) = 1 for every i ≠ 2. Evaluating the crossed
homomorphism with values δ_{ij} on the generators on the relator gives, for j ≥ 3, the vanishing
of 1 - χ(x_k) for the partner x_k of x_j in the commutator part; for j = 2 the vanishing of
χ(x₁) - 1; and for j = 1 the equation q + χ(x₂)⁻¹ - 1 = 0.
The standard orientation of the q ≠ 2 normal form has the prescription property: for
1 < n, the character with χ(x₂) = u, u (1 - q) = 1, and χ(x_i) = 1 otherwise.
Uniqueness of the canonical character of the q ≠ 2 normal form: for p ∣ q and n ≥ 2
even, a character with the prescription property is the orientation with marked value its value
χ(x₂).
The q ≠ 2 normal form has exactly one character with the prescription property (Labute,
Theorem 4, for the normal form x₁^q (x₁, x₂)(x₃, x₄) ⋯ (x_{n-1}, x_n) with p ∣ q and n ≥ 2
even): the standard orientation, with χ(x₂) = (1 - q)⁻¹ and χ(x_i) = 1 otherwise.
The q = 2, n odd normal form #
The tabulated values give the prescription property, q = 2 and n odd (Labute,
Theorem 4, existence). A continuous character of the pro-2 group presented by
x₁² x₂^{2^f} (x₂, x₃) ⋯ (x_{n-1}, x_n) with χ(x₁) = -1, χ(x₃) (1 - 2^f) = 1 and χ(x_i) = 1
otherwise has the prescription property.
The prescription property forces χ(x₁) = -1 on the q = 2, n odd normal form, for
n ≥ 1, whenever the relator x₁² x₂^{2^f} (x₂, x₃) ⋯ (x_{n-1}, x_n) lies in the Frattini
subgroup, as it does for f ≥ 1 (TauCeti.demushkinWordTwoOdd_mem_proPFrattini) and at rank one
for every f, where it reads x₁²: the crossed homomorphism with F(x₁) = 1 and F(x_i) = 0
otherwise takes the value χ(x₁) + 1 on the relator. This is the one clause of the forced
computation that survives at rank one.
The prescription property forces the tabulated values, q = 2 and n odd (Labute,
Theorem 4, the forced computation on a derivation). For f ≥ 1 and n ≥ 3 odd, a continuous
character of the pro-2 group presented by x₁² x₂^{2^f} (x₂, x₃) ⋯ (x_{n-1}, x_n) has the
prescription property exactly when χ(x₁) = -1, χ(x₃) (1 - 2^f) = 1 and χ(x_i) = 1 for every
other i.
The standard orientation of the q = 2, n odd normal form has the prescription
property: for 2 < n, the character with χ(x₁) = -1, χ(x₃) = u, u (1 - 2^f) = 1, and
χ(x_i) = 1 otherwise.
Uniqueness of the canonical character of the q = 2, n odd normal form: for f ≥ 1 and
n ≥ 3 odd, a character with the prescription property is the orientation with marked value its
value χ(x₃).
The q = 2, n odd normal form has exactly one character with the prescription property
(Labute, Theorem 4, for the normal form x₁² x₂^{2^f} (x₂, x₃) ⋯ (x_{n-1}, x_n) with f ≥ 1 and
n ≥ 3 odd): the standard orientation, with χ(x₁) = -1, χ(x₃) = (1 - 2^f)⁻¹ and χ(x_i) = 1
otherwise.
The prescription property in rank one (Labute, Remark 2 (iii)). On one generator the
q = 2, n odd word x₁² x₂^{2^f} reads x₁² for every level f, the presented group is
ℤ/2, and a continuous character has the prescription property exactly when χ(x₁) = -1: on the
relator x₁² every crossed homomorphism takes the value (χ(x₁) + 1) F(x₁).
ℤ/2, presented on one generator by x₁², has exactly one character with the prescription
property, the sign character χ(x₁) = -1, for every level f.
The q = 2, n odd normal form at level f = ∞ #
The tabulated values give the prescription property, q = 2 and n odd, at level
f = ∞ (Labute, Theorem 4, existence). A continuous character of the pro-2 group presented by
x₁² (x₂, x₃) ⋯ (x_{n-1}, x_n) with χ(x₁) = -1 and χ(x_i) = 1 otherwise has the prescription
property: on the relator, every crossed homomorphism for χ ∘ mk takes the value
(χ(x₁) + 1) F(x₁) = 0.
The prescription property forces χ(x₁) = -1 on the q = 2, n odd normal form at level
f = ∞, for n ≥ 1: the crossed homomorphism with F(x₁) = 1 and F(x_i) = 0 otherwise
takes the value χ(x₁) + 1 on the relator x₁² (x₂, x₃) ⋯ (x_{n-1}, x_n).
The prescription property forces the tabulated values, q = 2 and n odd, at level
f = ∞ (Labute, Theorem 4, the forced computation on a derivation). For n odd, a continuous
character of the pro-2 group presented by x₁² (x₂, x₃) ⋯ (x_{n-1}, x_n) has the prescription
property exactly when χ(x₁) = -1 and χ(x_i) = 1 for every other i. At n = 1 this is the
rank-one statement for ℤ/2.
The standard orientation of the q = 2, n odd normal form at level f = ∞ has the
prescription property, for 0 < n.
Uniqueness of the canonical character of the q = 2, n odd normal form at level
f = ∞: for n odd, a character with the prescription property is the standard orientation.
The q = 2, n odd normal form at level f = ∞ has exactly one character with the
prescription property (Labute, Theorem 4, for the normal form x₁² (x₂, x₃) ⋯ (x_{n-1}, x_n)
with n odd): the standard orientation, with χ(x₁) = -1 and χ(x_i) = 1 otherwise.
The q = 2, n even normal form with a 2-adic exponent #
The tabulated values give the prescription property (Labute, Theorem 4, existence). A
continuous character of the pro-2 group presented by
x₁^{2+α} (x₁, x₂) x₃^q (x₃, x₄) ⋯ (x_{n-1}, x_n) with χ(x₂) (1 + α) = -1, with
χ(x₄) (1 - q) = 1 when the factor x₃^q is present (2 < n), and with χ(x_i) = 1 otherwise
has the prescription property.
The prescription property forces the tabulated values (Labute, Theorem 4). For α even,
n ≥ 2 even and q even whenever the factor x₃^q is present (2 < n), a continuous character
of the pro-2 group presented by x₁^{2+α} (x₁, x₂) x₃^q (x₃, x₄) ⋯ (x_{n-1}, x_n) has the
prescription property exactly when χ(x₂) (1 + α) = -1, χ(x₄) (1 - q) = 1 when the factor
x₃^q is present, and χ(x_i) = 1 for every other i. At n = 2 the relator is
x₁^{2+α} (x₁, x₂) whatever q is, and the conditions read χ(x₂) (1 + α) = -1 and
χ(x₁) = 1.
The q = 2, n even normal form #
The tabulated values give the prescription property, q = 2 and n even (Labute,
Theorem 4, existence). A continuous character of the pro-2 group presented by
x₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n) with χ(x₂) (1 + a) = -1,
χ(x₄) (1 - 2^f) = 1 and χ(x_i) = 1 otherwise has the prescription property. This is the case
α = a, q = 2^f of
TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoEvenPadic_of_apply_eq.
The prescription property forces the tabulated values, q = 2 and n even (Labute,
Theorem 4). For 2 ∣ a, f ≥ 1 and n ≥ 4 even, a continuous character of the pro-2 group
presented by x₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n) has the prescription property
exactly when χ(x₂) (1 + a) = -1, χ(x₄) (1 - 2^f) = 1 and χ(x_i) = 1 for every other i.
This is the case α = a, q = 2^f of
TauCeti.hasPrescriptionProperty_presentedProP_demushkinWordTwoEvenPadic_iff.
The standard orientation of the q = 2, n even normal form has the prescription
property: for 3 < n, the character with χ(x₂) = v, v (1 + a) = -1, χ(x₄) = u,
u (1 - 2^f) = 1, and χ(x_i) = 1 otherwise.
Uniqueness of the canonical character of the q = 2, n even normal form: for 2 ∣ a,
f ≥ 1 and n ≥ 4 even, a character with the prescription property is the orientation with
marked values its values χ(x₂), χ(x₄).
The q = 2, n even normal form has exactly one character with the prescription
property (Labute, Theorem 4, for the normal form
x₁^{2+a} (x₁, x₂) x₃^{2^f} (x₃, x₄) ⋯ (x_{n-1}, x_n) with 2 ∣ a, f ≥ 1 and n ≥ 4 even): the
standard orientation, with χ(x₂) = -(1 + a)⁻¹, χ(x₄) = (1 - 2^f)⁻¹ and χ(x_i) = 1
otherwise.
The q = 2 normal form of rank two #
On two generators the even normal form is the rank-two word x₁^{2+a} (x₁, x₂), with no level:
only the marked value on x₂ remains.
The tabulated values give the prescription property in rank two, q = 2: a continuous
character of the pro-2 group presented by x₁^{2+a} (x₁, x₂) with χ(x₁) = 1 and
χ(x₂) (1 + a) = -1 has the prescription property.
The prescription property forces the tabulated values in rank two, q = 2 (Labute,
Theorem 4 and Remark, the case n = 2). For 2 ∣ a, a continuous character of the pro-2 group
presented by x₁^{2+a} (x₁, x₂) has the prescription property exactly when χ(x₁) = 1 and
χ(x₂) (1 + a) = -1.
Uniqueness of the canonical character of the rank-two q = 2 normal form: for 2 ∣ a, a
character with the prescription property is the orientation with marked value its value χ(x₂).
The rank-two q = 2 normal form has exactly one character with the prescription property
(Labute, Theorem 4, for the normal form x₁^{2+a} (x₁, x₂) with 2 ∣ a): the standard
orientation, with χ(x₁) = 1 and χ(x₂) = -(1 + a)⁻¹.