ℤ/2 is the unique Demushkin group of rank one #
A Demushkin group of rank one is procyclic: it is topologically generated by a single element a.
If a has infinite order the group is ℤ_p, the free pro-p group on one generator, whose
H²(-, 𝔽_p) vanishes, so it is not Demushkin. Otherwise the group is a finite cyclic p-group
ℤ/pᵏ. The rank is odd, so p = 2 by the parity constraint. For k ≥ 2 the mod-2 character
of ℤ/2ᵏ lifts to ℤ/4, so its cup square vanishes
(ContinuousMonoidHom.cupFp_zmodFourReductionClass_self_eq_zero); but in a Demushkin group of
rank one H¹(G, 𝔽_p) is a line, so nondegeneracy of the cup pairing forces the cup square of every
nonzero class to be nonzero. Hence k = 1, and the group is ℤ/2, which is Demushkin
(TauCeti.isDemushkin_multiplicative_zmod_two).
Along the way, a group topologically isomorphic to ℤ/n is shown not to be Demushkin at p = 2
whenever 4 ∣ n; this covers the cyclic groups ℤ/2ᵏ with k ≥ 2.
Main results #
TauCeti.IsDemushkin.cupFp_self_ne_zero_of_demushkinRank_eq_one: in a Demushkin group of rank one, every nonzero class ofH¹(G, 𝔽_p)has nonzero cup square.TauCeti.not_isDemushkin_of_four_dvd_of_continuousMulEquiv_multiplicative_zmod: a group topologically isomorphic toℤ/nis not Demushkin atp = 2when4 ∣ n.TauCeti.IsDemushkin.eq_two_of_demushkinRank_eq_one: a Demushkin group of rank one lives atp = 2.TauCeti.IsDemushkin.nonempty_continuousMulEquiv_multiplicative_zmod_two_of_demushkinRank_eq_one: a Demushkin group of rank one is topologically isomorphic toℤ/2.TauCeti.IsDemushkin.demushkinRank_eq_one_iff: a Demushkin group has rank one exactly when it is topologically isomorphic toℤ/2.
References #
- J. P. Labute, Classification of Demushkin groups, Canad. J. Math. 19 (1967), 106–132, p. 106 and Remark 2.
- J.-P. Serre, Galois Cohomology, Springer (1997), Chapter I, §4.5.
- J. Neukirch, A. Schmidt, K. Wingberg, Cohomology of Number Fields, 2nd ed., Springer (2008), (3.9.10).
In a Demushkin group of rank one, every nonzero class of H¹(G, 𝔽_p) has nonzero cup
square: H¹(G, 𝔽_p) is a line, so the class pairing nontrivially with a nonzero a is a
multiple of a.
A Demushkin group at p = 2 admitting a continuous character to ℤ/4 with an odd value does
not have rank one: the reduction modulo 2 of the character is a nonzero class of H¹(G, 𝔽₂)
with vanishing cup square.
A profinite group topologically isomorphic to ℤ/n with 4 ∣ n is not Demushkin at
p = 2: it has rank one, and its mod-2 character lifts to ℤ/4.
A Demushkin group of rank one lives at p = 2: at an odd prime the rank is even.
ℤ/2 is the unique Demushkin group of rank one: a Demushkin group of rank one is
topologically isomorphic to ℤ/2. It is procyclic; a generator of infinite order would make it
free pro-p of rank one, whose H² vanishes; a generator of finite order makes it a finite cyclic
group ℤ/2ᵏ, and for k ≥ 2 the mod-2 character lifts to ℤ/4, so its cup square vanishes,
against the nondegeneracy of the cup pairing on the line H¹(G, 𝔽₂).
A Demushkin group has rank one exactly when it is topologically isomorphic to ℤ/2.