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TauCeti.Topology.Algebra.Group.Profinite.Demushkin.Rank.One

ℤ/2 is the unique Demushkin group of rank one #

A Demushkin group of rank one is procyclic: it is topologically generated by a single element a. If a has infinite order the group is ℤ_p, the free pro-p group on one generator, whose H²(-, 𝔽_p) vanishes, so it is not Demushkin. Otherwise the group is a finite cyclic p-group ℤ/pᵏ. The rank is odd, so p = 2 by the parity constraint. For k ≥ 2 the mod-2 character of ℤ/2ᵏ lifts to ℤ/4, so its cup square vanishes (ContinuousMonoidHom.cupFp_zmodFourReductionClass_self_eq_zero); but in a Demushkin group of rank one H¹(G, 𝔽_p) is a line, so nondegeneracy of the cup pairing forces the cup square of every nonzero class to be nonzero. Hence k = 1, and the group is ℤ/2, which is Demushkin (TauCeti.isDemushkin_multiplicative_zmod_two).

Along the way, a group topologically isomorphic to ℤ/n is shown not to be Demushkin at p = 2 whenever 4 ∣ n; this covers the cyclic groups ℤ/2ᵏ with k ≥ 2.

Main results #

References #

In a Demushkin group of rank one, every nonzero class of H¹(G, 𝔽_p) has nonzero cup square: H¹(G, 𝔽_p) is a line, so the class pairing nontrivially with a nonzero a is a multiple of a.

A Demushkin group at p = 2 admitting a continuous character to ℤ/4 with an odd value does not have rank one: the reduction modulo 2 of the character is a nonzero class of H¹(G, 𝔽₂) with vanishing cup square.

A profinite group topologically isomorphic to ℤ/n with 4 ∣ n is not Demushkin at p = 2: it has rank one, and its mod-2 character lifts to ℤ/4.

A Demushkin group of rank one lives at p = 2: at an odd prime the rank is even.

ℤ/2 is the unique Demushkin group of rank one: a Demushkin group of rank one is topologically isomorphic to ℤ/2. It is procyclic; a generator of infinite order would make it free pro-p of rank one, whose H² vanishes; a generator of finite order makes it a finite cyclic group ℤ/2ᵏ, and for k ≥ 2 the mod-2 character lifts to ℤ/4, so its cup square vanishes, against the nondegeneracy of the cup pairing on the line H¹(G, 𝔽₂).

A Demushkin group has rank one exactly when it is topologically isomorphic to ℤ/2.