Continuous inverses of shifts of partial linear maps #
For a partial linear map A on a module over a ring, LinearPMap.IsResolventAt
says that a continuous linear map inverts lambda โข I - A on the domain of A. The inverse
is unique, and its existence defines LinearPMap.resolventSet and the chosen map
LinearPMap.resolvent. These notions require only a topology on the module, with no norm or
continuity assumptions on addition or scalar multiplication.
Over a noncommutative ring, the scalar expression x โฆ lambda โข x - A x need not be linear.
The predicate still requires its inverse to be linear over the full scalar ring; a parameter
whose shift is not linear therefore does not belong to the resolvent set.
This file gives the graph characterization, the two inverse identities, and the fact that an
operator has no proper extension sharing a resolvent point. On normed spaces the continuous
linear inverse is bounded; the normed resolvent theory and its bridge to Mathlib's
Banach-algebra resolvent are developed in
TauCeti.Analysis.Normed.Operator.Resolvent.Unbounded.
References #
Engel--Nagel, One-Parameter Semigroups for Linear Evolution Equations, Section IV.1; Pazy, Semigroups of Linear Operators and Applications to Partial Differential Equations, Chapter 1.
Inverting lambda โข I - A #
IsResolventAt A lambda R says that the continuous operator R : X โL[๐] X inverts
lambda โข I - A : D(A) โ X: it takes its values in D(A), is a right inverse of
lambda โข I - A on all of X, and is a left inverse of it on D(A).
For an unbounded A this replaces the Banach-algebra condition
IsUnit (algebraMap ๐ (X โL[๐] X) lambda - A) behind Mathlib's resolventSet, which cannot be
formed because A is not an element of X โL[๐] X. The two conditions agree when A is a
bounded operator read as an everywhere defined LinearPMap; the bridge is developed in
TauCeti.Analysis.Normed.Operator.Resolvent.Unbounded.
The inverse takes its values in the domain of
A.Ris a right inverse:(lambda โข I - A) (R y) = yfor everyy : X.Ris a left inverse:R ((lambda โข I - A) x) = xfor everyx โ D(A).
Instances For
An inverse of lambda โข I - A is unique: a left inverse and a right inverse of the same
map agree.
lambda โข I - A is injective on D(A) whenever it has a left inverse.
lambda โข I - A maps D(A) onto X whenever it has a right inverse.
lambda โข I - A : D(A) โ X is a bijection at a point of the resolvent set.
The graph form of IsResolventAt: R inverts lambda โข I - A exactly when every
(R y, lambda โข R y - y) lies on the graph of A, and R (lambda โข x - w) = x for every point
(x, w) of that graph. This form transfers along any construction described by its graph.
The resolvent set and the resolvent #
The resolvent set of an unbounded operator A : X โโ.[๐] X: those lambda : ๐ for which
lambda โข I - A : D(A) โ X is a bijection with continuous linear inverse.
Equations
- A.resolventSet = {lambda : ๐ | โ (R : X โL[๐] X), A.IsResolventAt lambda R}
Instances For
Membership in the resolvent set unfolds to the existence of a continuous linear inverse of
lambda โข I - A.
Exhibiting an inverse puts lambda in the resolvent set.
The resolvent R(lambda, A) = (lambda โข I - A)โปยน of an unbounded operator, as a
continuous linear operator on X.
Off the resolvent set the value is an unspecified junk value; every lemma below carries the
hypothesis lambda โ resolventSet A. Uniqueness of the inverse
(LinearPMap.IsResolventAt.unique) makes the choice immaterial on the
resolvent set: LinearPMap.resolvent_eq_of_isResolventAt identifies it with
any inverse one can exhibit.
Instances For
On the resolvent set, resolvent A lambda really does invert lambda โข I - A.
Any exhibited inverse of lambda โข I - A is the resolvent.
The resolvent takes its values in D(A).
The right-inverse identity (lambda โข I - A) R(lambda) y = y.
The left-inverse identity R(lambda) (lambda โข x - A x) = x on D(A).
The right-inverse identity solved for A: A R(lambda) y = lambda โข R(lambda) y - y.
At a point of the resolvent set, lambda โข I - A : D(A) โ X is a bijection.
An operator has no proper extension sharing a resolvent point. If A โค B and some
lambda lies in the resolvent set of both, then A = B.
A vector y โ D(B) has lambda โข y - B y = lambda โข x - A x for a unique x โ D(A), by
surjectivity for A; injectivity for B then forces y = x, so D(B) โ D(A).
This is the step that upgrades "A is a restriction of the generator" to "A is the
generator" in the generation theorems.
The resolvent commutes with A on D(A): R(lambda) (A x) = A (R(lambda) x).