The nonlinear Hardy graph of a plumbing node #
Let 0 < |a| < 1. The neck of the plumbing xy = a is the annulus |a| ≤ |x| ≤ 1 in the first
branch coordinate, with outer boundary circles |x| = 1 and |y| = 1. A holomorphic embedding of
the neck into the node zw = b is x ↦ (f(x), b / f(x)) for a nonvanishing holomorphic f of
winding number one on the annulus. Its boundary values are ξ = f on |x| = 1 and
η(y) = b / f(a / y) on |y| = 1, so they satisfy the node equation ξ(x) η(a / x) = b.
The nonlinear Hardy graph theorem says that, near the identity pair (ξ, η) = (x, y), the
positive Fourier coefficients of ξ and η are free parameters, and the nonpositive coefficients
and b are determined by them, holomorphically in a and the parameters, including at the node
a = 0.
This file proves this in exponential coordinates ξ = x e^F, η = y e^G, with F and G in the
circle Sobolev space H^s, s > 1/2. In these coordinates the node equation becomes the linear
equation F(x) + G(a / x) = F₀ + G₀, with b = a e^{F₀ + G₀}. In Fourier coefficients this says
that (F, G) lies in the neck graph CircleSobolev.neckGraph s ℂ a
(CircleSobolev.hasSum_zpow_smul_coeff_of_mem_neckGraph); the multiplicative form is
CircleSobolev.mul_exp_mul_mul_exp_eq_of_mem_neckGraph. The positive coefficients of ξ = x e^F
are the nonnegative coefficients of e^F, shifted by one. So the theorem asks to solve
indicator (Set.Ici 0) (e^F) = 1 + p, indicator (Set.Ici 0) (e^G) = 1 + q,
(F, G) ∈ neckGraph s ℂ a
for (F, G) near 0, given a near 0 and nonnegative-frequency p, q near 0. Here e^F
is the holomorphic Nemytskii map CircleSobolev.nemytskii exp F.
The neck graph is the graph of the bounded operator CircleSobolev.neckTransfer a over the
nonnegative Laurent subspaces, which depends holomorphically on a and vanishes at a = 0. After
substituting this parametrization, the equation is a holomorphic equation in a, p, q and the
nonnegative parts of F and G, whose derivative in the last two variables at the origin is the
identity, because the derivative of e^F at F = 0 is the identity
(CircleSobolev.hasFDerivAt_nemytskii_zero). The holomorphic implicit function theorem then gives
the solution and its local uniqueness.
Main statements #
TauCeti.CircleSobolev.mul_exp_mul_mul_exp_eq_of_mem_neckGraph: for(F, G)in the neck graph anda ≠ 0, the node equationξ(x) η(a / x) = a e^{F₀ + G₀}forξ = x e^F,η = y e^G, the valueη(a / x)being given by the Laurent series ofG.TauCeti.CircleSobolev.exists_analyticAt_hardyGraph: the nonlinear Hardy graph theorem, with a solution map analytic in(a, p, q)and unique in a fixed neighbourhood of0.
References #
- J. W. Robbin and D. A. Salamon, A construction of the Deligne–Mumford orbifold, J. Eur. Math. Soc. 8 (2006), 611–699, §§9–12 (Hardy decompositions at the nodes of a plumbed Riemann surface).
The node equation. For s > 1/2, a ≠ 0 and (F, G) in the neck graph, the boundary maps
ξ = x e^F on |x| = 1 and η = y e^G on |y| = 1 satisfy ξ(x) η(a / x) = a e^{F₀ + G₀} at
every point x = fourier 1 x of the unit circle, where η(a / x) is evaluated through the
convergent Laurent series G(a / x) = ∑ₙ (a / x)ⁿ Gₙ.
The nonlinear Hardy graph theorem at a plumbing node. For s > 1/2 there are a
neighbourhood W of 0 in H^s × H^s and a map ψ, analytic at the origin with ψ 0 = 0, such
that for all data y = (a, p, q) near 0, with p and q of nonnegative frequencies, ψ y is
the unique (F, G) ∈ W with
(F, G)in the neck graph of the plumbingxy = a, and- nonnegative parts of
e^Fande^Gequal to1 + pand1 + q.
In terms of the boundary maps ξ = x e^F and η = y e^G, the conditions say that (ξ, η) solves
the node equation ξ(x) η(a / x) = b with b = a e^{F₀ + G₀}
(CircleSobolev.mul_exp_mul_mul_exp_eq_of_mem_neckGraph), and that the positive Fourier
coefficients of ξ and η are those of x (1 + p) and y (1 + q). So the solution, its
nonpositive coefficients and b depend holomorphically on a and on these positive coefficients,
also at the node a = 0.