Totally isotropic submodules #
A submodule W of M is totally isotropic for a quadratic map Q when Q vanishes on every
vector of W, that is, when the restriction of Q to W is zero.
Main definitions #
QuadraticMap.IsTotallyIsotropic: a submodule on which a quadratic map vanishes.
Main results #
QuadraticMap.isTotallyIsotropic_iff_restrict_eq_zero: total isotropy is the vanishing of the restricted form.QuadraticMap.isTotallyIsotropic_comp_iff: total isotropy forQ.comp fis total isotropy of the image underf.QuadraticMap.maximal_isTotallyIsotropic_bot_iff: the zero submodule is maximal totally isotropic exactly when the form is anisotropic.QuadraticMap.IsTotallyIsotropic.eq_zero_of_polar_eq_zero: for a nondegenerate form andW ⊔ W' = ⊤withW'totally isotropic, a vector ofW'which is polar-orthogonal toWvanishes.QuadraticMap.IsTotallyIsotropic.finrank_eq_of_codisjoint: two totally isotropic subspaces spanning a nondegenerate quadratic space have the samefinrank(the dimension when finite, and0for both otherwise).
The Witt-index comparison for maximal totally isotropic subspaces (Lam I.4.4) is in
TauCeti.LinearAlgebra.QuadraticForm.Witt.TotallyIsotropic.
A submodule W is totally isotropic for a quadratic map Q when Q vanishes on every
vector of W.
Instances For
Unfolds QuadraticMap.IsTotallyIsotropic.
A quadratic map vanishes on each vector of a totally isotropic submodule.
A submodule is totally isotropic exactly when the restriction of the form to it is zero.
A submodule is totally isotropic for Q.comp f exactly when its image under f is totally
isotropic for Q.
The preimage of a totally isotropic submodule under a linear map f is totally isotropic
for Q.comp f.
A submodule of U is totally isotropic for the restriction of Q to U exactly when it is
totally isotropic for Q as a submodule of M.
The vectors of U lying in a totally isotropic submodule W form a totally isotropic
submodule for the restriction of Q to U.
The zero submodule is totally isotropic.
A submodule of a totally isotropic submodule is totally isotropic.
A line is totally isotropic exactly when its spanning vector is isotropic.
The zero subspace is a maximal totally isotropic subspace exactly when the form is anisotropic.
The polar form vanishes on pairs of vectors of a totally isotropic submodule.
For a nondegenerate Q, if W ⊔ W' = ⊤ with W' totally isotropic, a vector of W'
which is polar-orthogonal to W vanishes: it is then polar-orthogonal to all of M = W + W',
hence lies in the radical.
For a nondegenerate Q and W ⊔ W' = ⊤ with W' totally isotropic, the polar pairing of
W' with W is injective in the W' variable.
If W is finite-dimensional and W ⊔ W' = ⊤ with W' totally isotropic in a nondegenerate
space, then W' is finite-dimensional: the polar pairing embeds W' into the dual of W.
If W is finite-dimensional and W ⊔ W' = ⊤ with W' totally isotropic in a nondegenerate
space, then W' has dimension at most that of W: the polar pairing embeds W' into the dual
of W.
Two totally isotropic subspaces spanning a nondegenerate quadratic space have the same
Module.finrank: the polar pairing embeds each into the dual of the other. This is the equality
of their dimensions when they are finite-dimensional, and otherwise both finranks are 0.