Totally isotropic subspaces and the Witt index #
A subspace W of a quadratic space (V, Q) is totally isotropic
(QuadraticMap.IsTotallyIsotropic) when Q vanishes on every vector of W. Over a field in
which 2 is invertible, every maximal totally isotropic subspace of a regular finite-dimensional
quadratic space has dimension equal to the Witt index of Q (Lam I.4.4). The Witt index,
defined by TauCeti.RegularFormClass.wittIndex as the number of hyperbolic planes in the Witt
decomposition Q ≅ m × ℍ ⊥ Q_a, is therefore intrinsic to the quadratic space: it is the common
dimension of its maximal totally isotropic subspaces, and the largest dimension of a totally
isotropic subspace.
Main results #
QuadraticForm.finrank_eq_wittIndex_of_maximal: Lam I.4.4, a maximal totally isotropic subspace of a regular space has dimension the Witt index.QuadraticMap.IsTotallyIsotropic.finrank_le_wittIndex: every totally isotropic subspace of a regular space has dimension at most the Witt index.QuadraticMap.IsTotallyIsotropic.exists_le_finrank_eq_wittIndex: every totally isotropic subspace of a regular space lies in one whose dimension is the Witt index.QuadraticForm.maximal_isTotallyIsotropic_iff: a totally isotropic subspace of a regular space is maximal exactly when its dimension is the Witt index.
Implementation notes #
The comparison goes by induction on the dimension. A nonzero vector w of a maximal totally
isotropic subspace W has an isotropic partner f with polar Q w f = 1. The span of w and
f is a hyperbolic plane, its orthogonal complement U has Witt index one less, and W ∩ U is a
maximal totally isotropic subspace of U of dimension one less.
References #
- T. Y. Lam, Introduction to Quadratic Forms over Fields (2005), Chapter I, §4.
Splitting a hyperbolic pair off a totally isotropic subspace #
Throughout, w ∈ W lies in a totally isotropic subspace W and f satisfies polar Q w f = 1.
Write U for the orthogonal complement of the span of w and f. Then W is the direct sum of
the line through w and W ∩ U, and W ∩ U is maximal in U when W is maximal in V.
Lam I.4.4. Every maximal totally isotropic subspace of a regular finite-dimensional quadratic space has dimension the Witt index of the form.
Every totally isotropic subspace of a regular finite-dimensional quadratic space lies in a totally isotropic subspace whose dimension is the Witt index.
Every totally isotropic subspace of a regular finite-dimensional quadratic space has dimension at most the Witt index.
A totally isotropic subspace of a regular finite-dimensional quadratic space is maximal exactly when its dimension is the Witt index: the maximal totally isotropic subspaces are those of largest dimension.