Newman's Tauberian theorem for bounded Laplace transforms #
Let f : ℝ → ℂ be measurable and bounded by M on [0, ∞), and let G be holomorphic on an
open set Ω containing the closed half-plane 0 ≤ re z, agreeing with the Laplace transform
∫ t in Ici 0, f t * exp (-z t) on 0 < re z. Newman's Tauberian theorem
(newmanLaplace_tendsto_integral) states that the improper integral ∫ t in 0..T, f t
converges to G 0 as T → ∞.
The proof assembles the contour estimates of the neighbouring files. Fix R > 0 and choose a
detour newmanDetour R δ through the left half-plane inside Ω. With
G_T z = ∫ t in 0..T, f t * exp (-z t) and Newman's kernel k_T z = exp (T z) (1 + z² / R²) / z:
- Cauchy's formula for
(G - G_T) k_Ton the right semicircle closed by the detour, together with the deformation of the left semicircle into the detour for the entire functionG_T, givesintegral_right_semicircle_add_integral_newmanDetour_mul_kernel: the right semicircle integral of(G - G_T) k_Tplus the detour integral ofG k_Tequals2πi (G 0 - ∫ t in 0..T, f t)plus the left semicircle integral ofG_T k_T; - the two semicircle contributions are at most
M / Rafter division by2πi, and the detour integral ofG k_Ttends to0asT → ∞, so eventually‖G 0 - ∫ t in 0..T, f t‖ ≤ 2 M / R + ε(eventually_norm_sub_intervalIntegral_le); - letting
R → ∞gives the theorem.
No radius-independent continuation width is used: the detour depends on R.
Since the Laplace transform is already holomorphic on 0 < re z, the continuation hypothesis
only concerns the imaginary axis: newmanLaplace_tendsto_integral_of_analyticAt asks instead that
G be analytic at each point of re z = 0.
References #
- D. J. Newman, Simple analytic proof of the prime number theorem, Amer. Math. Monthly 87 (1980), 693–696.
- D. Zagier, Newman's short proof of the prime number theorem, Amer. Math. Monthly 104 (1997), 705–708.
Newman's contour identity. Let G be holomorphic on an open convex set U containing
the right semicircle of radius R > 0 and the detour newmanDetour R δ with δ > 0, and let
G_T z = ∫ t in 0..T, f t * exp (-z t). Against Newman's kernel
k_T z = exp (T z) (1 + z² / R²) / z, the right semicircle integral of (G - G_T) k_T
(counterclockwise from -R * I to R * I) plus the detour integral of G k_T (from R * I
back to -R * I) equals 2πi (G 0 - ∫ t in 0..T, f t) plus the left semicircle integral of
G_T k_T (counterclockwise from R * I to -R * I). All integrals include the velocity of
their parametrization.
Newman's estimate at a fixed radius. Let f be measurable and bounded by M on
[0, ∞), and let G be holomorphic on an open set Ω containing the closed half-plane
0 ≤ re z and equal to the Laplace transform of f on 0 < re z. For every R > 0 and
ε > 0, eventually in T, ‖G 0 - ∫ t in 0..T, f t‖ ≤ 2 M / R + ε.
Newman's Tauberian theorem. Let f : ℝ → ℂ be measurable and bounded on [0, ∞), and
let G be holomorphic on an open set Ω containing the closed half-plane 0 ≤ re z, agreeing
with the Laplace transform ∫ t in Ici 0, f t * exp (-z t) on the open half-plane 0 < re z.
Then ∫ t in 0..T, f t converges to G 0 as T → ∞.
Newman's Tauberian theorem, with a pointwise continuation hypothesis. Let f : ℝ → ℂ be
measurable and bounded on [0, ∞), and let G agree with the Laplace transform
∫ t in Ici 0, f t * exp (-z t) on the open half-plane 0 < re z and be analytic at every point
of the imaginary axis re z = 0. Then ∫ t in 0..T, f t converges to G 0 as T → ∞.
Since the Laplace transform is holomorphic on 0 < re z, this hypothesis on G is equivalent to
holomorphy on an open set containing the closed half-plane 0 ≤ re z, as in
newmanLaplace_tendsto_integral.