The Tate cup product with a degree-zero class #
For a finite group G and representations M, N, this file constructs the Tate cup product
tateCohomology M n × tateCohomology N 0 → tateCohomology (M ⊗ N) n
in every integer degree n. An invariant y ∈ N^G gives a morphism of representations
M ⟶ M ⊗ N, m ↦ m ⊗ y, and the cup product of x ∈ tateCohomology M n with the class of y
is the image of x under the induced map. The substance is that this depends only on the class of
y in tateCohomology N 0 = N^G / N_G N: when y = N_G z is a norm, m ↦ m ⊗ N_G z is the norm
m ↦ ∑ g, g • (g⁻¹ • m ⊗ z) of the linear map m ↦ m ⊗ z, so it factors through a coinduced
representation and induces zero on Tate cohomology.
This is the bidegree (n, 0) part of the cup product on Tate cohomology. It is compatible with the
connecting homomorphisms in the first variable, and the cup product of two degree-zero classes is
induced by M^G ⊗ N^G → (M ⊗ N)^G; these are the two properties from which the cup product in all
bidegrees is obtained by dimension shifting (Cassels–Fröhlich, Chapter IV, §7).
Main definitions #
TauCeti.TateCohomology.cupH0: the cup producttateCohomology M n × tateCohomology N 0 → tateCohomology (M ⊗ N) n, as ak-bilinear map.
Main statements #
TauCeti.TateCohomology.map_tensorInvariant_eq_zero:m ↦ m ⊗ yinduces zero on Tate cohomology whenyis a norm.TauCeti.TateCohomology.cupH0_H0π: the cup product with the class of an invariantyis the map induced bym ↦ m ⊗ y.TauCeti.TateCohomology.cupH0_H0π_H0π: in degree zero, the cup product of the classes ofxandyis the class ofx ⊗ y.TauCeti.TateCohomology.cupH0_map_left,TauCeti.TateCohomology.cupH0_map_right: naturality in both coefficient representations.TauCeti.TateCohomology.δ_cupH0: compatibility with the connecting homomorphism of a short exact sequence in the first variable which stays short exact after tensoring withN.
References #
- J. W. S. Cassels and A. Fröhlich (eds.), Algebraic Number Theory, Chapter IV (Atiyah–Wall), §6 and §7.
- K. S. Brown, Cohomology of Groups, Chapter VI, §5.
If y is a norm, then m ↦ m ⊗ y induces zero on Tate cohomology in every degree: for
y = N_G z it is the norm m ↦ ∑ g, g • (g⁻¹ • m ⊗ z) of the linear map m ↦ m ⊗ z.
The Tate cup product with a degree-zero class,
tateCohomology M n × tateCohomology N 0 → tateCohomology (M ⊗ N) n: the cup product of x with
the class of an invariant y is the image of x under the map induced by m ↦ m ⊗ y
(cupH0_H0π). It is well defined because that map vanishes on Tate cohomology when
y is a norm (map_tensorInvariant_eq_zero).
Instances For
The cup product with the class of an invariant y is the map induced by m ↦ m ⊗ y.
In degree zero, the cup product of the classes of invariants x and y is the class of the
invariant x ⊗ y.
The cup product with a degree-zero class is natural in the first coefficient representation.
The cup product with a degree-zero class is natural in the second coefficient representation.
The cup product with a degree-zero class commutes with the connecting homomorphism in the
first variable: for a short exact sequence 0 → M₁ → M₂ → M₃ → 0 which stays short exact after
tensoring with N (for instance one that splits k-linearly), δ (x ∪ y) = δ x ∪ y.