The constrained span statement at the normal form x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n) #
Let F = freeProP p (Fin n) with n even, let r be the normal-form word
TauCeti.demushkinWordNeTwo q n on the generators of F with p ∣ q, and let ρ ∈ gr_1(F) be
its class. Throughout this file indices are the 0-based indices of Fin n: x_j = of j is the
j-th generator, ξ_j its class in gr_0(F), and ∂_j is the partial derivative
TauCeti.freeProP.degreeOneDeriv p (Fin n) j at x_j; in these indices the word is
r = x_0^q (x_0, x_1)(x_2, x_3) ⋯ (x_{n-2}, x_{n-1}). The partial derivatives of ρ at the
generators other than x_0 are ∂_{2a+1} ρ = -ξ_{2a} whenever 2a + 1 < n, and
∂_{2a} ρ = ξ_{2a+1} whenever 1 ≤ a and 2a + 1 < n
(TauCeti.freeProP.degreeOneDeriv_gradedMk_demushkinWordNeTwo_odd,
TauCeti.freeProP.degreeOneDeriv_gradedMk_demushkinWordNeTwo_even). So every generator class
ξ_j with j ≠ 1 is a combination of these derivatives, which is the hypothesis of the
constrained span statement of Free/ExponentSumKernel.lean with i₀ = 0 and i₁ = 1. The
conclusion is Labute's Lemma 3: for the kernel X of the exponent sum at x_1 and every m ≥ 1,
gr_{m+1}(X) = δ_ρ(gr_m(X)^n) + T_{m+1},
where T_{m+1} is spanned by the π^{m+1} ξ_j with j ≠ 1. This is the span statement that the
uniqueness argument for the dyadic even-rank Demushkin groups with orientation image U^[f] runs
on: their relator x₁^{2+2^f} (x₁, x₂)(x₃, x₄) ⋯ is this word at p = 2 and q = 2 + 2^f, the
orientation is the exponent sum at x_1 composed with γ ↦ χ(x_1)^γ, and the basis corrections
must be taken inside its kernel.
Main results #
TauCeti.freeProP.degreeOneDeriv_gradedMk_demushkinWordNeTwo_odd,TauCeti.freeProP.degreeOneDeriv_gradedMk_demushkinWordNeTwo_even,TauCeti.freeProP.degreeOneDeriv_gradedMk_demushkinWordNeTwo_zero: the partial derivatives of the class of the word at the generators.gradedPieceOf_exponentSumKer_demushkinWordNeTwo_eq_map_basisModificationDelta_sup(inTauCeti.freeProP): the constrained span statement at this normal form.
References #
- J. P. Labute, Classification of Demushkin groups, Canad. J. Math. 19 (1967), 106–132, §4, Lemmas 1–3 and the proof of Theorem 5.
The derivative of the class of x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n) at the generator x_{2a}
(in the 0-based indexing of Fin n), for a ≥ 1: ∂_{2a} ρ = ξ_{2a+1}.
The derivative of the class of x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n) at the generator x_{2a+1}
(in the 0-based indexing of Fin n): ∂_{2a+1} ρ = -ξ_{2a}.
The derivative of the class of x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n) at the generator x_0 (in
the 0-based indexing of Fin n), for n ≥ 2: ∂_0 ρ = (q / p) • (p choose 2) • ξ_0 + ξ_1, the
first term from the p-power factor x_0^q and the second from the bracket [ξ_0, ξ_1].
Every generator class other than ξ_1 is a combination of the derivatives at the generators
other than x_0 (in the 0-based indexing of Fin n), for the class of
x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n) with n even.
The constrained span statement at the normal form x₁^q (x₁, x₂) ⋯ (x_{n-1}, x_n)
(Labute, §4, Lemma 3). For n even, p ∣ q, the class ρ of the word, X the kernel of the
exponent sum at the generator x_1 (in the 0-based indexing of Fin n) and every m ≥ 1,
gr_{m+1}(X) = δ_ρ(gr_m(X)^n) + T_{m+1},
where the tail T_{m+1} is spanned by the p-powers π^{m+1} ξ_j with j ≠ 1. At p = 2 and
q = 2 + 2^f this is the span statement for the relators x₁^{2+2^f} (x₁, x₂)(x₃, x₄) ⋯ whose
basis corrections must respect the orientation.