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TauCeti.FieldTheory.GaloisGroups.Quartic.Examples

The five quartic labels over ℚ #

One monic integral quartic for each of the five transitive-group labels of degree four, with its label proved through the quartic decision table of TauCeti.FieldTheory.GaloisGroups.Quartic.Basic.

polynomialresolvent cubicdiscriminantlabel
X⁴ + X + 1X³ - 4X - 1, irreducible229, not a squareS₄ = 4T5
X⁴ + 8X + 12X³ - 48X - 64, irreducible331776 = 576²A₄ = 4T4
X⁴ - 2X³ + 8X, one rational root-2048, not a squareD₄ = 4T3
X⁴ + 1X³ - 4X, splits completely256 = 16²V₄ = 4T2
X⁴ + X³ + X² + X + 1X³ - X² - 3X + 2, one root125, not a squareC₄ = 4T1

The table decides the first, second and fourth rows outright. The third and fifth rows are only placed in the pair {4T1, 4T3} by the table, and a further datum separates them. For X⁴ + X³ + X² + X + 1 = Φ₅ the Galois group is (ℤ/5)ˣ of order four, the order of 4T1 and not of 4T3. For X⁴ - 2 the reduction modulo 7 factors as (X - 2)(X - 5)(X² + 4), so by Dedekind's theorem the Galois image contains a transposition, which fixes two roots; a group with the cyclic label 4T1 has as many elements as there are roots, so it acts freely on them and contains no such element.

Irreducibility over ℚ is proved by Gauss's lemma for X⁴ + X + 1 and X⁴ + 8X + 12, ruling out integral roots and integral monic quadratic factors by reduction modulo 2 and 5; by the Eisenstein criterion at 2 for X⁴ - 2; and from the irreducibility of the cyclotomic polynomials Φ₈ = X⁴ + 1 and Φ₅ over ℚ.

Main results #

References #

X ^ 4 + X + 1: the symmetric group, 4T5 #

X ^ 4 + X + 1 is irreducible over ℚ: it has no root modulo 2, and a monic quadratic factor X² + aX + b would force 1 = a³ - 2ab and 1 = a²b - b², which has no solution modulo 2.

The discriminant of X ^ 4 + X + 1 is 229.

The resolvent cubic X ^ 3 - 4 * X - 1 of X ^ 4 + X + 1 is irreducible over ℚ: it has no root modulo 3, so no integral root.

X ^ 4 + X + 1 has label 4T5: its Galois group over ℚ is the symmetric group on its four roots. The discriminant 229 is prime, hence not a square, and the resolvent cubic is irreducible.

The Galois group of X ^ 4 + X + 1 over ℚ has order 24.

X ^ 4 + 8 * X + 12: the alternating group, 4T4 #

X ^ 4 + 8 * X + 12 is irreducible over ℚ: it is positive at every integer, being (m² - 2)² + 4 (m + 1)² + 4, and a monic quadratic factor X² + aX + b would force 8 = a³ - 2ab and 12 = a²b - b², which has no solution modulo 5.

The resolvent cubic of X ^ 4 + 8 * X + 12 is X ^ 3 - 48 * X - 64.

The discriminant of X ^ 4 + 8 * X + 12 is 331776 = 576 ^ 2.

The resolvent cubic X ^ 3 - 48 * X - 64 of X ^ 4 + 8 * X + 12 is irreducible over ℚ: it has no root modulo 5, so no integral root.

X ^ 4 + 8 * X + 12 has label 4T4: its Galois group over ℚ is the alternating group on its four roots. The discriminant 576 ^ 2 is a square and the resolvent cubic is irreducible.

The Galois group of X ^ 4 + 8 * X + 12 over ℚ has order 12.

X ^ 4 + 1: the Klein four-group, 4T2 #

X ^ 4 + 1 is the eighth cyclotomic polynomial, hence irreducible over ℚ.

The resolvent cubic of X ^ 4 + 1 is X ^ 3 - 4 * X, which splits completely over ℚ.

The discriminant of X ^ 4 + 1 is 256 = 16 ^ 2.

X ^ 4 + 1 has label 4T2: its Galois group over ℚ is the Klein four-group acting regularly on its four roots, the primitive eighth roots of unity. The discriminant 16 ^ 2 is a square and the resolvent cubic X ^ 3 - 4 * X has the root 0.

The Galois group of X ^ 4 + 1 over ℚ has order 4.

X ^ 4 + X ^ 3 + X ^ 2 + X + 1: the cyclic group, 4T1 #

X ^ 4 + X ^ 3 + X ^ 2 + X + 1 is the fifth cyclotomic polynomial, hence irreducible over ℚ.

The Galois group of X ^ 4 + X ^ 3 + X ^ 2 + X + 1 over ℚ has order 4: it is the unit group of ℤ/5.

The resolvent cubic of X ^ 4 + X ^ 3 + X ^ 2 + X + 1 is X ^ 3 - X ^ 2 - 3 * X + 2, with the rational root 2.

The discriminant of X ^ 4 + X ^ 3 + X ^ 2 + X + 1 is 125 = 5 ^ 3.

X ^ 4 + X ^ 3 + X ^ 2 + X + 1 has label 4T1: its Galois group over ℚ is cyclic of order four, acting regularly on the primitive fifth roots of unity. The discriminant 125 is not a square and the resolvent cubic has the rational root 2, which places the label in {4T1, 4T3}; the order 4 of the Galois group rules out 4T3, of order 8.

X ^ 4 - 2: the dihedral group, 4T3 #

X ^ 4 - 2 is irreducible over ℚ, by the Eisenstein criterion at the prime 2.

The resolvent cubic of X ^ 4 - 2 is X ^ 3 + 8 * X, with the rational root 0.

The discriminant of X ^ 4 - 2 over ℚ is -2048 = -2 ^ 11.

The discriminant of X ^ 4 - 2 over ℤ is -2048 = -2 ^ 11, so every odd prime is a good prime for X ^ 4 - 2.

Modulo 7, X ^ 4 - 2 factors as (X - 2)(X - 5)(X ^ 2 + 4), where X ^ 2 + 4 is irreducible because -4 = 3 is not a square modulo 7. Its factor degrees are {1, 1, 2}.

X ^ 4 - 2 does not have cyclic Galois group. Modulo 7 it factors with exactly one quadratic factor, so by Dedekind's theorem its Galois image contains a transposition, which fixes two of the four roots. A group with the cyclic label 4T1 has order four and acts freely on the four roots, so it contains no such element.

X ^ 4 - 2 has label 4T3: its Galois group over ℚ is dihedral of order eight. The discriminant -2048 is not a square and the resolvent cubic X ^ 3 + 8 * X has the rational root 0, which places the label in {4T1, 4T3}; the transposition exhibited by the factorization modulo 7 rules out 4T1.

The Galois group of X ^ 4 - 2 over ℚ has order 8.